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Bukhovtsev-et-al-Problems-in-Elementary-Physics

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ELECTRICITY AND MAGNETISM<br />

295<br />

Fig. 409 Fig. 410<br />

where T 1 and T 2 are the tensions of the thread, <strong>al</strong> and ~ the angles of<br />

deflection of the thread, + Q and ~ Q the charges of the fixed b<strong>al</strong>ls, + Qs<br />

the charge of the suspended b<strong>al</strong>l, and mg is the weight of the suspended<br />

b<strong>al</strong>l (Fig. 409).<br />

Upon exclud<strong>in</strong>g the unknowns from the above simultaneous equations, we<br />

g<strong>et</strong><br />

cot a 1 -cot a 2=cot ai-cot 2<strong>al</strong> =2(V2-1)<br />

whence,<br />

cot <strong>al</strong>=2 (2 Y2 - 1) ± V35-16 Y 2<br />

Thus, C&J. =7°56' and a,=15°52' when mg > ~~s ( 1--':2 ), and<br />

<strong>al</strong>=82°04' and a 2=164°OB' when mg < ~~s (1--':2 ).<br />

399. In uniform motion the drop is acted upon by the force of gravity G.<br />

the expulsive force of the air (Archimedean force) F, the force of the electrostatic<br />

field eE and the force of friction aga<strong>in</strong>st the air kv=k ~ . All the forces<br />

are b<strong>al</strong>anced. Therefore,<br />

G-F-eEO+k..!..=O<br />

t 1<br />

G-F+eE-k~=O<br />

t;<br />

G-F-k!..=O<br />

t<br />

where e is the charge of the drop, E the <strong>in</strong>tensity of the electric field, and s<br />

the distance covered by the drop.

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