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Bukhovtsev-et-al-Problems-in-Elementary-Physics

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ELECTRICITY AND MAGNETISM 359<br />

A ......---...<br />

Fig. 470<br />

B<br />

tude of 180 V) plus the same vol..<br />

tage of the charged eapaeitor. The<br />

change <strong>in</strong> the potent ia I <strong>al</strong>ong the<br />

circuit at this moment of time is<br />

shown <strong>in</strong> Fig. 470.<br />

If the rectifier operates without<br />

load, the capacitor should be c<strong>al</strong>eufated<br />

for a punctur<strong>in</strong>g volta ge of at<br />

least 180 V, and the diode for a<br />

voltage of at least 360 V.<br />

604. The anode voltage of each<br />

diode is<br />

U a = ~<br />

s<strong>in</strong> rot-IR<br />

A current flows through the diode when Ua > 0 and does not flow through<br />

it when V a ~ O. In a quarter of a period the current will not flow dur<strong>in</strong>g<br />

the time <strong>in</strong>terv<strong>al</strong> 0 ~ t ~ t 1 (Fig. 471). where t 1 is d<strong>et</strong>erm<strong>in</strong>ed by the equation<br />

I/o<br />

-JH<br />

Fig. 471<br />

~ s<strong>in</strong> rot.-IR=0. Hence, t. = ~ arc s<strong>in</strong> 2~R . This is <strong>al</strong>so the time dur<strong>in</strong>g<br />

which the current does not flow <strong>in</strong> the follow<strong>in</strong>g quarters of the period.<br />

Altog<strong>et</strong>her <strong>in</strong> a period the current does not flow dur<strong>in</strong>g<br />

2T . 2/R<br />

"""it arc s<strong>in</strong> ---0-=0.465 T<br />

3-6. Electric<strong>al</strong> Mach<strong>in</strong>es<br />

605. If the frequency of the <strong>al</strong>ternat<strong>in</strong>g current rema<strong>in</strong>s the same, this<br />

means that the revolutions of the motor and the generator <strong>al</strong>so rema<strong>in</strong> as<br />

before. and the e.rn.I. of the generator wHI not change.<br />

When the extern<strong>al</strong> resistance <strong>in</strong> the circuit is high, the circuit will carry<br />

a sm<strong>al</strong>ler current and a lower power will be supplied. For this reason the<br />

power of the motor that revolves the generator should be reduced.<br />

606. The work performed by a field <strong>in</strong> mov<strong>in</strong>g conductors carry<strong>in</strong>g a current<br />

(armature w<strong>in</strong>d<strong>in</strong>gs) is not equ<strong>al</strong> to the tot<strong>al</strong> work of the field. Apart from<br />

the work spent to move the conductors, the magn<strong>et</strong>ic field performs work to

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