28.08.2016 Views

Bukhovtsev-et-al-Problems-in-Elementary-Physics

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

248 ANSWERS AND SOLUTIONS<br />

1-9. The Law of Gravitation<br />

220. Accord<strong>in</strong>g to Newton's second law, mig==F, where m, is the <strong>in</strong>erti<strong>al</strong><br />

mass-a quantity that characterizes the ability of bodies to acquire an acceleration<br />

under the <strong>in</strong>fluence of a def<strong>in</strong>ite force.<br />

mM<br />

On the other hand, accord<strong>in</strong>g to the law of gravitation F='V ~2 g, where<br />

y is the gravity constant and m g and Mg are the gravitation<strong>al</strong> masses of<br />

the <strong>in</strong>teract<strong>in</strong>g bodies. The gravitation<strong>al</strong> mass d<strong>et</strong>erm<strong>in</strong>es the force of gravity<br />

and, <strong>in</strong> this sense, can be referred to as a gravitation<strong>al</strong> charge.<br />

It is not obvious <strong>in</strong> advance that mi=m g • If this equation (proportion<strong>al</strong>ity<br />

is sufficient) is satisfied, however, the gravity acceleration is the same for <strong>al</strong>l<br />

bodies s<strong>in</strong>ce, when the gravity force is <strong>in</strong>troduced <strong>in</strong>to Newton's second law,<br />

the masses mj and m g can be cancelled, and g will be equ<strong>al</strong> to y ; .<br />

Identic<strong>al</strong> accelerations are imparted to <strong>al</strong>l bodies irrespective of their<br />

masses, only by the force of gravity.<br />

221. The gravitation<strong>al</strong> acceleration g=y ~ (see Problem 220). Assum<strong>in</strong>g<br />

that g=982 em/s, we f<strong>in</strong>d that y=6.68X 10- 8 ems,-1 S-2.<br />

222. The bodies <strong>in</strong>side the spaceship will cease to exert any pressure on<br />

the w<strong>al</strong>ls of the cab<strong>in</strong> if they have the same acceleration as the spaceship.<br />

Only the force of gravity can impart an identic<strong>al</strong> acceleration <strong>in</strong> this space<br />

to <strong>al</strong>l the bodies irrespective of their mass. Consequently, it is essenti<strong>al</strong> that<br />

the eng<strong>in</strong>e of the spaceship be shut off and there be no resistance of the<br />

extern<strong>al</strong> medium. The spaceship may move <strong>in</strong> any direction with respect to<br />

that of the force of gravity.<br />

223. The force of gravity imparts the same acceleration to the pendulum<br />

and the block. Gravity does not cause any deformations <strong>in</strong> the system dur<strong>in</strong>g<br />

free f<strong>al</strong>l<strong>in</strong>g. For this reason the pendulum will so move with respect to the<br />

block as if there is no gravitation (see the solution to Problem 222). The<br />

pendulum will move with a constant angular velocity as long as the block<br />

f<strong>al</strong>ls.<br />

224. On section Be A (Fig. 371) the force of gravity performs positive work<br />

(the angle 9 1 is acute) and the velocity of the plan<strong>et</strong> will <strong>in</strong>crease, reach<strong>in</strong>g<br />

its maximum at po<strong>in</strong>t A.<br />

~<br />

C<br />

B<br />

"<br />

"\\\<br />

,<br />

I<br />

I<br />

I I<br />

, /'<br />

Fig. 311 Fig. 372

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!