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Bukhovtsev-et-al-Problems-in-Elementary-Physics

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CHAPTER 6<br />

PHYSICAL<br />

OPTICS<br />

6-1. Interference of Light<br />

763. NOt it does not. The presence of Illum<strong>in</strong>ation m<strong>in</strong>ima on the <strong>in</strong>terference<br />

pattern means that no quantity of light enters the given section of<br />

space. /<br />

764. The maximum illum<strong>in</strong>ation will be observed at an arbitrary po<strong>in</strong>t of<br />

the screen C (Fig. 550) if the difference of the paths d l-d1 =kA, where<br />

k=O, 1, 2, ... is an <strong>in</strong>teger.<br />

Accord<strong>in</strong>g to the Pythagorean theorem,<br />

d: = DI+( hk +;r<br />

d~=D'+( hk - ;r<br />

whence<br />

d:-d~=(d,+dl)<br />

(d,-dt)=2hlc'<br />

In accordance with ~he <strong>in</strong>iti<strong>al</strong> conditlon d, +d t ~ 2D. Therefore, d, -d 1 ==<br />

= k). ~ 2:~' . The distance tothe k-th light band from the centre of the screen is<br />

h,,-= k~D • The distance b<strong>et</strong>ween the bands is Ah=hk+l-hk=).f .<br />

785. The distance b<strong>et</strong>ween Interference bands is Ah=~ (see Problem 764).<br />

In our case D==AB es:a+b, and 1=8 1 8, is the distance b<strong>et</strong>ween the images<br />

Sl and 52 of the source <strong>in</strong> the ftat mirrors (Fig. 551). The v<strong>al</strong>ue of I can<br />

r----------------------------<br />

I<br />

IIII<br />

c<br />

4 1 ~~~-----D -------:l~<br />

Fig. 550

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