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Phương trình lượng giác 11 ( đầy đủ lí thuyết bài tập )

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⎡ π<br />

⎡ π<br />

⎢2x + 1 = − 2 + x + k2π x 3 k2<br />

2<br />

⎢ = − + π<br />

⇔<br />

2<br />

⎢<br />

⇔ ⎢<br />

, k ∈Z .<br />

⎢ π<br />

π 1 k2π<br />

2x + 1 = + 2 − x + k2π<br />

⎢x<br />

= + +<br />

⎢⎣ 2<br />

⎢⎣<br />

6 3 3<br />

Bài 5. Giải phương <strong>trình</strong> 2 cos x − 2 = 0<br />

π<br />

π<br />

A. x = ± + k2 π, ( k ∈Z )<br />

B. x = ± + k2 π, ( k ∈Z )<br />

6<br />

5<br />

π<br />

π<br />

C. x = ± + k2 π, ( k ∈Z )<br />

D. x = ± + k2 π, ( k ∈Z )<br />

3<br />

4<br />

Lời giải:<br />

<strong>Phương</strong> <strong>trình</strong><br />

2 π π<br />

⇔ cos x = = cos ⇔ x = ± + k2 π, ( k ∈Z )<br />

2 4 4<br />

Bài 6. Giải phương <strong>trình</strong><br />

2x 2 cot = 3<br />

3<br />

A.<br />

C.<br />

5 3 3<br />

x = arc cot + kπ ( k ∈Z )<br />

2 2 2<br />

B.<br />

3 3 3<br />

x = arc cot + kπ ( k ∈Z )<br />

2 7 2<br />

D.<br />

3 5 3<br />

x = arc cot + kπ ( k ∈Z )<br />

2 2 2<br />

3 3 3<br />

x = arc cot + kπ ( k ∈Z )<br />

2 2 2<br />

Lời giải:<br />

<strong>Phương</strong> <strong>trình</strong><br />

2x<br />

3 2x<br />

3<br />

⇔ cot = ⇔ = arc cot + kπ<br />

3 2 3 2<br />

3 3 3<br />

⇔ x = arc cot + kπ ( k ∈Z ) .<br />

2 2 2<br />

Bài 7. Giải phương <strong>trình</strong><br />

1<br />

sin(4 x − π ) =<br />

3 2<br />

π<br />

π<br />

A. x = + kπ,<br />

k ∈Z B. x = + kπ,<br />

k ∈Z<br />

2<br />

3<br />

π<br />

C. x = + kπ,<br />

k ∈Z D. x = kπ,<br />

k ∈Z<br />

5<br />

Lời giải:<br />

⎛ π ⎞ ⎛ π ⎞<br />

<strong>Phương</strong> <strong>trình</strong> ⇔ tan⎜ 3x<br />

− ⎟ = tan⎜ − ⎟<br />

⎝ 3 ⎠ ⎝ 3 ⎠<br />

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