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Phương trình lượng giác 11 ( đầy đủ lí thuyết bài tập )

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π<br />

2<br />

π 2 π<br />

= + , ∈Z C.<br />

2 3<br />

A. x = + kπ,<br />

( k ∈Z )<br />

B. x k ( k )<br />

π<br />

x k k<br />

2<br />

π<br />

3<br />

= + 2 π,( ∈Z)<br />

D. x = + k2 π,<br />

( k ∈Z )<br />

<strong>Phương</strong> <strong>trình</strong><br />

Lời giải:<br />

2π<br />

2π<br />

⇔ sin x − = k2π ⇔ sin x = 1+<br />

3k<br />

3 3<br />

π<br />

Do −1 ≤ sin x ≤ 1 ⇒ k = 0 ⇒ x = + k2π<br />

2<br />

⎡π ⎤<br />

cot ⎢ cos 1 = −1<br />

4<br />

⎥<br />

⎣<br />

⎦<br />

Bài 28. Giải phương <strong>trình</strong> ( x − )<br />

π<br />

2<br />

π π<br />

2 2<br />

π π<br />

2 3<br />

A. x = + 2 kπ,<br />

( k ∈Z )<br />

B. x = + k ,( k ∈Z ) C. x = + k ,( k ∈Z)<br />

π<br />

2<br />

D. x = + kπ,<br />

( k ∈Z )<br />

π<br />

π<br />

⇔ − = − + kπ<br />

4 4<br />

<strong>Phương</strong> <strong>trình</strong> ( cos x 1)<br />

Lời giải:<br />

π<br />

⇔ cos x = 4k ⇒ k = 0 ⇒ cos x = 0 ⇔ x = + kπ.<br />

2<br />

Bài 29. Giải phương <strong>trình</strong> 3 sin 2x<br />

− cos 2x<br />

+ 1 = 0<br />

⎡ x = kπ<br />

A. ⎢<br />

( k ∈Z )<br />

B. ⎢<br />

( k ∈ )<br />

⎢<br />

π<br />

x = + kπ<br />

⎢⎣ 3<br />

⎡ x = 2kπ<br />

⎢<br />

⎢<br />

2π<br />

x = + 2kπ<br />

⎢⎣ 3<br />

⎡ x = kπ<br />

( k ∈Z ) D. ⎢<br />

( k ∈Z<br />

)<br />

⎢<br />

2π<br />

x = + kπ<br />

⎢⎣ 3<br />

⎡ x = kπ<br />

⎢<br />

2π<br />

x = + 2kπ<br />

⎢⎣ 3<br />

Z C.<br />

<strong>Phương</strong> <strong>trình</strong><br />

Lời giải:<br />

⎡ x = kπ<br />

⎛ π ⎞ 1<br />

⇔ sin 2x<br />

⎢<br />

⎜ − 2<br />

6<br />

⎟ = − ⇔ π<br />

⎝ ⎠ 2 ⎢ x = + kπ<br />

⎢⎣ 3<br />

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