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Thermal Food Processing

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136 <strong>Thermal</strong> <strong>Food</strong> <strong>Processing</strong>: New Technologies and Quality Issues<br />

the average velocity. As such, the turbulence regime provides a more uniform<br />

mixing condition for thermal processing. The average residence time is the length<br />

of the pipe divided by the average velocity; thus, the microbes that travel at the<br />

maximum velocity would not be fully processed.<br />

This is related to aseptic processing, where food is sterilized or pasteurized<br />

in a tubular, helical heat exchanger, scraped-surface heat exchanger, microwave,<br />

or ohmic heater. The aseptic process has significant quality advantages over<br />

classical thermal techniques, such as batch (canning) and semibatch operations.<br />

In general, flow modeling has to be used to ensure that food products meet the<br />

safety requirements. It determines the optimal lengths of the heating, holding,<br />

and cooling sections.<br />

5.2.2 THERMAL RESISTANCE CONSTANT Z<br />

The thermal resistance constant Z is a parameter representing the microorganism’s<br />

resistance to temperature rise:<br />

5.2.3 THERMAL DEATH TIME F<br />

(5.8)<br />

The thermal death time F is the time required to cause a stated reduction in the<br />

population of microorganisms or spores. This time is expressed as a multiple of<br />

D values. A 99.99% reduction in microbial population is equivalent to 4D, for<br />

instance. Usually, F is expressed as F z<br />

T for a specific temperature T and a thermal<br />

resistance constant z.<br />

5.2.4 RELATIONSHIPS BETWEEN CHEMICAL KINETICS<br />

AND THERMAL PROCESSING PARAMETERS<br />

It is generally accepted that at a constant temperature, the microbial population<br />

or number concentration (microbe· m –3 ) (N) reduces following the first-order<br />

reaction:<br />

Therefore, the solution for this is<br />

T2 − T1<br />

Z =<br />

DT1<br />

log<br />

D<br />

dN<br />

dt<br />

T2<br />

=−k⋅N ln N<br />

=−k⋅t N<br />

o<br />

(5.9)<br />

(5.10)

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