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Bias Circuit

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11.3 Operational Amplifier Offset<br />

Ideally, an opamp is balanced such that the dc output is zero (with dual power supply) with<br />

zero input voltage (as in Fig. 11.1). In practice, this is not realized, due to the variation of<br />

parameters between similar transistors and components. As mentioned above, the opamp<br />

configuration of Fig. 11.1 will probably be locked at near the positive or negative rail voltage.<br />

Thus, a given opamp requires an input voltage Vin to set the output to zero. The magnitude of<br />

this voltage is defined as offset voltage Voff.<br />

An equivalent circuit that includes the offset voltage is given in Fig. 11.6. The imperfections of<br />

the amplifier are reflected into the offset voltage and the opamp is ideal. If Vi is made equal to<br />

Voff, the output VO will be zero. Suppose that Vi = 0. In this case we have the equivalent of Voff<br />

applied to the input and the output is driven toward the plus or minus power-supply voltages<br />

(depending on the polarity of Voff). Voff is usually large enough to cause the amplifier to be<br />

driven out of the active mode. For example, a typical Voff is Voff = 1 mV. Thus, if avo = 40,000,<br />

the output will attempt to become –40 V, which is probably greater than the supply voltage<br />

value; the output is set at the negative limit. In our project opamp, this will be roughly VSS +<br />

50 mV if driven negative or VDD –1V if driven toward the positive supply.<br />

Figure 11.6. Ideal opamp with offset voltage. With dc input voltage Vi<br />

= Voff, VO = 0. Witt Vi = 0 (grounded input), VO VDD or VSS with<br />

|avoVoff| > VDD or |VSS| for Voff negative or positive, respectively.

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