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Bias Circuit

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etween the drain and source of the transistor, but the circuit as given is equivalent, as the<br />

source is at ground. Since the output voltage is Vo = –IRDRD, the new gain result is<br />

Equation 5.4<br />

Note that this form evolves from ideal transistor current, gmVgs, flowing through the parallel<br />

combination of the output resistance and RD.<br />

To facilitate an intuitive grasp of the magnitude of the effect of gds, we use the expression for<br />

gds (4.13) in (5.4), to obtain<br />

Equation 5.5<br />

Note that IDRD is the voltage drop across RD. For example, for a –10-V power supply, we<br />

choose IDRD 5 V. A measurement of λp for our devices will show that λp 1/20 V, which<br />

results in λpIDRD<br />

1/4. Thus, the effect of gds (= λpID) for this case is significant.<br />

Finally, we can get an overall current dependence for av with the elimination of gm, using(4.5)<br />

with kp, which results in<br />

Equation 5.6<br />

Using an alternative form for gm (= 2ID/Veffp), also (4.5), the gain expression is<br />

Equation 5.7<br />

where<br />

For simplicity, approximate forms of (4.5) and (4.13) of gm and gds are used here, which are<br />

independent of VSD. For reference, the "exact" and approximate forms of (4.5) and (4.13),<br />

respectively, are repeated here:

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