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Fugacity: It is derived from Latin, expressed as fleetness or escaping ...

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F<strong>or</strong> the re<strong>as</strong>ction C2H4 + ½ O2 ↔ C2H4O, develop equations f<strong>or</strong> ΔH 0 , K, and ΔG 0 , find<br />

ΔG 0 at 550 K<br />

Cp (Cal / mol K) Data: C2H4 = 3.68 + 0.0224 T<br />

Standard heat of reaction ΔH 0 298<br />

C2H4O = - 12 190 and C2H4 = - 12 500, Cal / mol<br />

Re action 298<br />

In th<strong>is</strong> problem C<br />

p<br />

<br />

H H H<br />

Pr oducts Re ac tan ts<br />

T<br />

O2<br />

And ΔG 0 298 = -19070 Cal / mol<br />

1 <br />

= 1.59 3.68 6.39 5.285<br />

Pr oducts Re ac tan ts<br />

2 <br />

= 6.39 + 0.0021 T<br />

C2H4O = 1.59 + .00332 T<br />

= 1(-12190) – 1( -12500) = 310 Cal / mol<br />

1 <br />

= 0.0332 0.0224 0.0021 0.00975<br />

Pr oducts Re ac tan ts<br />

2 <br />

Then the variation of standard heat of reaction with temperature <strong>is</strong>

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