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Fugacity: It is derived from Latin, expressed as fleetness or escaping ...

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The hydration of Ethylene to alcohol <strong>is</strong> given by C2H2 + H2O C2H5OH<br />

Temperature 0 C 145 6.8 x 10 -2<br />

Equilibrium Constant 320 1.9 x 10 -3<br />

The heat capacity data f<strong>or</strong> the component can be<br />

represented by Cp = a + bT where T <strong>is</strong> in kelvin<br />

and Cp <strong>is</strong> in cal / g mol 0 C<br />

Develop general expression f<strong>or</strong> the equilibrium constant and standard Gibb’s free<br />

energy change <strong>as</strong> function of temperature.<br />

<br />

a a a = 6.99(2.83 7.3) 3.14 <br />

Pr oducts Re ac tan ts<br />

<br />

b b b 39.741x10(28.6 10 x 2.46 10) x 8.68 10 x<br />

Pr oducts Re ac tan ts<br />

a b c<br />

I<br />

lnK = ln<br />

R 2R 6R<br />

RT<br />

2<br />

T T T M<br />

3 3 3 3<br />

3<br />

3.14<br />

8.68x10 I<br />

lnK = lnT<br />

T M<br />

2 2x2 2T<br />

3<br />

-2 3.14<br />

8.68x10 I <br />

At 418 K,<br />

ln 6.8x10 = ln 418 418 M <br />

2 2x2 2x418 <br />

Solving,<br />

I = -9655.807 & M = -5.667<br />

3<br />

-3 3.14<br />

8.68x10 I<br />

593 K, ln 1.9x10 ln593 593<br />

At M <br />

2 2x2 2x593 <br />

3<br />

3.14<br />

8.68x10 -9655.807<br />

lnK = lnT<br />

T <br />

-5.667<br />

2 2x2 2T<br />

3<br />

3.14 8.68x10 -9655.807 <br />

But G = -2T lnT T -5.667<br />

2 2x2 2T<br />

<br />

-3 2<br />

G = 3.14T ln T - 4.34x10 T 9655.807 11.334T<br />

Component a bx10 3<br />

C2H4 2.83 28.601<br />

H2O 7.3 2.46<br />

C2H5OH<br />

6.99 39.741

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