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Fugacity: It is derived from Latin, expressed as fleetness or escaping ...

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o 2 <br />

3 0.00975 2<br />

H T T T I 5.285 T T I<br />

2 3 2<br />

0 0.00975 2<br />

Given H298 =310 = 5.285 T T I then I = 1452<br />

2<br />

o<br />

0.00975 2 0<br />

H 5.285 T T 1452 Th<strong>is</strong> <strong>is</strong> variation of H298<br />

with temparature<br />

2<br />

2 I 5.285<br />

0.00975 1452<br />

lnK = ln T T T M = lnT<br />

T M<br />

R 2R 6R RT 2 2(2) 2T<br />

0<br />

0 G298 19070<br />

but G298 RT ln K298<br />

<strong>or</strong> lnK298 32<br />

RT 2(298)<br />

5.285<br />

0.00975 1452<br />

32 = ln298 298 M theref<strong>or</strong>e M = 48.763<br />

2 2(2) 2(298)<br />

5.285<br />

0.00975 1452<br />

lnK = lnT T 48.763<br />

2 4 2T<br />

0<br />

G RT lnK 2T<br />

lnK<br />

5.285 0.00975 1452 <br />

2T lnK 2T lnT T 48.763<br />

2 4 2T<br />

<br />

<br />

0 3<br />

2<br />

G 5.285T lnT 4.875(10)() T 1452 97.526() T<br />

G 5.285(550)ln550 4.875(10)(550) 1452 97<br />

.526(550)<br />

0<br />

550<br />

3<br />

2<br />

G 35320.62<br />

Cal / mol<br />

0<br />

550<br />

50 mol% each of SO2 and O2 <strong>is</strong> fed to a converter to f<strong>or</strong>m SO3.<br />

Show the variation of i) Standard heat of reaction with T ii) Equilibrium constant<br />

with T. The ΔHf and ΔGf at 298 K are<br />

Component<br />

ΔHf<br />

k Cal / k<br />

mol<br />

ΔGf<br />

k Cal / k<br />

mol<br />

SO2 -70960 -71680<br />

O2 0 0<br />

SO3 -94450 -88590

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