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Fugacity: It is derived from Latin, expressed as fleetness or escaping ...

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Feed contains 50 mole% SO2 and O2.Th<strong>is</strong> means f<strong>or</strong> every one mole SO2 there will be<br />

one mole O2 in the reactant side and ½ mole O2 in the product side, acc<strong>or</strong>ding to SO2 +<br />

½ O2 SO3<br />

Reactants: 1 mol SO2 + 1 mol O2 Products: 1 mol SO3 + ½ mol O2 (excess)<br />

1<br />

= 6.0377 + 6.148 7.116 6.148 - 4.152<br />

2<br />

Pr oducts reac tan ts<br />

-3<br />

= 23.53(10) +<br />

Pr oducts reac tan ts<br />

0 2 <br />

3<br />

H T T T I<br />

2 3<br />

-3<br />

12.474x10 2<br />

= -4.152T+<br />

T I<br />

2<br />

1<br />

3<br />

-3<br />

3.102(10) - 9.512 (10) + 3<br />

2<br />

<br />

-3<br />

.102 (10) <br />

=12.474<br />

x10<br />

-3<br />

0 0<br />

But H at 298 <strong>is</strong> given by H <br />

0<br />

H <br />

0<br />

H 94450 70960 23490<br />

k Cal / k mol<br />

298<br />

products Re ac tan ts<br />

-3 2<br />

-23490=-4.152 (298 ) + 6.237 x 10(298) <br />

<br />

I = -22818.19<br />

0<br />

3<br />

2<br />

H 4.152 T 6.237x10 T 22818.19<br />

Next f<strong>or</strong> K we have<br />

<br />

<br />

<br />

2 I<br />

lnK= lnT<br />

T T M<br />

R 2R 6R<br />

RT<br />

3<br />

4.152<br />

12.474x10 22818.19<br />

lnK= lnT<br />

T M<br />

2 2xR 2T<br />

I<br />

CP data:<br />

Component a b(10 3 )<br />

SO2 7.116 9.512<br />

O2 6.148 3.102<br />

SO3 6.0377 23.537

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