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Edge-connectivity of undirected and directed hypergraphs

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Section 4.3. Covering supermodular functions by <strong>directed</strong> <strong>hypergraphs</strong> 77<br />

if <strong>and</strong> only if<br />

hold for every partition F <strong>of</strong> V .<br />

γ ≥ <br />

p(X), (4.7)<br />

X∈F<br />

rγ ≥ <br />

p(V − X), (4.8)<br />

X∈F<br />

(|F| − 1) γ ≥ <br />

p(V − X) (4.9)<br />

X∈F<br />

Pro<strong>of</strong>. The necessity <strong>of</strong> the conditions can be seen easily. To prove sufficiency, one can<br />

construct degree specifications mi <strong>and</strong> mo that satisfy the conditions <strong>of</strong> Theorem 4.5. Let<br />

us define the set function p ′ by p ′ (X) := p(X) for X ⊂ V <strong>and</strong> p ′ (V ) := γ. Then p ′ is<br />

positively crossing supermodular. Since (4.7) <strong>and</strong> (4.9) hold for p ′ , by applying Theorem<br />

2.13 to p ′ we get a nonnegative integer vector mi such that mi(X) ≥ p(X) for all X ⊆ V ,<br />

<strong>and</strong> mi(V ) = γ.<br />

To construct mo let m ′ o be a nonnegative vector satisfying m ′ o(V − X) ≥ p(X) for<br />

all X ⊆ V , which is minimal in the sense that for every v ∈ V with m ′ o(v) > 0 there<br />

exists a set X for which v /∈ X <strong>and</strong> m ′ o(V − X) = p(X) (such a set is called tight). Let<br />

B = {X1, X2, . . . , Xl} be a family <strong>of</strong> minimum cardinality which for every node v with<br />

m ′ o(v) > 0 contains a tight set not containing v. Then B is cross-free, since we could<br />

replace a crossing pair Xi, Xj by their intersection according to (2.2). If the family is<br />

composed <strong>of</strong> co-disjoint sets, then<br />

m ′ o(V ) =<br />

l<br />

m ′ o(V − Xi) =<br />

i=1<br />

l<br />

p(Xi) ≤ rγ<br />

by (4.8). If there are two disjoint sets Xi <strong>and</strong> Xj in B, then<br />

m ′ o(V ) ≤ m ′ o(V − Xi) + m ′ o(V − Xj) = p(Xi) + p(Xj) ≤ γ.<br />

Thus we can obtain an out-degree specification mo by increasing m ′ o on an arbitrary node<br />

to obtain mo(V ) = rγ. By Theorem 4.5 there is a <strong>directed</strong> (r, 1)-hypergraph with degrees<br />

mi <strong>and</strong> mo that covers p.<br />

The following example demonstrates that condition (4.9) cannot be left out. Let V =<br />

{v1, v2, v3}, p({v1, v2}) = p({v1, v3}) = p({v2, v3}) := 2 <strong>and</strong> p(X) := 0 for the other sets,<br />

r := 3, γ := 2. Conditions (4.7) <strong>and</strong> (4.8) are satisfied, but (4.9) is not, <strong>and</strong> there is no<br />

<strong>directed</strong> (3, 1)-hypergraph <strong>of</strong> 2 hyperarcs covering p. When r = 1, i.e. we add digraph<br />

edges, (4.9) follows from (4.8).<br />

i=1

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