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PHYS08200604018 Shamik Banerjee - Homi Bhabha National ...

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This proves the desired result.<br />

Next we shall study the subgroup of S-duality transformations which takes a configuration<br />

with (r 1 = r, r 2 = 1, r 3 = 1, u 1 = 1) to another configuration with (r 1 = r, r 2 = 1, r 3 = 1, u 1 =<br />

1). The initial configuration has<br />

An S-duality transformation (3.0.3) takes this to<br />

Q = re 1 , P = e 1 + e 2 . (3.0.13)<br />

Q ′ = are 1 + b(e 1 + e 2 ) , P ′ = cre 1 + d(e 1 + e 2 ) . (3.0.14)<br />

In order that Q ′ is r times a primitive vector, we must demand<br />

Expressing b as b 0 r with b 0 ∈ Z we get<br />

where<br />

27<br />

b = 0 mod r . (3.0.15)<br />

Q ′ = re ′ 1, P ′ = e ′ 1 + e ′ 2 , (3.0.16)<br />

e ′ 1 = (a + b 0 )e 1 + b 0 e 2 , e ′ 2 = (cr + d − a − b 0 )e 1 + (d − b 0 )e 2 . (3.0.17)<br />

Since the determinant of the matrix relating (e ′ 1, e ′ 2) to (e 1 , e 2 ) is given by<br />

(a + b 0 )(d − b 0 ) − b 0 (cr + d − a − b 0 ) = ad − bc = 1 , (3.0.18)<br />

we conclude that (e ′ 1, e ′ 2) is a primitive basis of Λ 0 . Comparison with (3.0.2) now shows that<br />

(Q ′ , P ′ )( has r 1 ′ ) = r, r 2 ′ = r 3 ′ = u ′ 1 = 1 as required. Thus the only condition on the SL(2, Z)<br />

a b<br />

matrix for preserving the (r<br />

c d<br />

1 = r, r 2 = 1, r 3 = 1, u 1 = 1) condition is that it must<br />

have b = 0 mod r, ı.e. it must be an element of Γ 0 (r).<br />

Using this we can now determine the subgroup of SL(2, Z) that takes a pair of charge<br />

vectors (Q, P ) with invariants (r 1 , r 2 , r 3 , u 1 ) to another pair of charge vectors with ( the ) same<br />

a b<br />

invariants. For this we note that any SL(2, Z) transformation matrix g 0 = with<br />

c d<br />

a, b given in (3.0.8) takes the set (r 1 , r 2 , r 3 , u 1 ) to the set (r 1 r 2 r 3 , 1, 1, 1). Since the latter set<br />

is preserved by the Γ 0 (r) subgroup of SL(2, Z), the original set must be preserved by the<br />

subgroup g0 −1 Γ 0 (r)g 0 . This is isomorphic to the group Γ 0 (r).<br />

To see an example of this consider the case<br />

r 1 = r 2 = 1, r 3 = 2, u 1 = 1 . (3.0.19)<br />

( )<br />

1 1<br />

In this case the SL(2, Z) transformation g 0 = takes a configuration given in (3.0.19)<br />

0 1<br />

to a configuration with r 1 = 2, r 2 = r 3 = u 1 = 1. Thus the SL(2, Z) transformations which

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