07.01.2014 Views

PHYS08200604018 Shamik Banerjee - Homi Bhabha National ...

PHYS08200604018 Shamik Banerjee - Homi Bhabha National ...

PHYS08200604018 Shamik Banerjee - Homi Bhabha National ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

4.5. EXAMPLES 59<br />

uncorrelated and can take arbitrary integer values, it follows from (4.3.22) that at this zero ̂Φ<br />

goes as<br />

̂Φ(ˇρ, ˇσ s , ˇv s ) ∝ (2ˇv s + ˇσ s ) 2 φ m<br />

(ˇρ + 1 ) ( ) 1<br />

4 ˇσ s + ˇv s ; 1, 1 φ e<br />

4 ˇσ s; 1, 0 +O ( (2ˇv s + ˇσ s ) 4) . (4.5.2.29)<br />

φ m (τ; 1, 1) denotes the partition function of half-BPS states carrying charges (P, P ), with τ<br />

being conjugate to the variable P ′2 /2 = P 2 /2. Thus we have φ m (τ; 1, 1) = (η(τ)) 24 . On the<br />

other hand (φ e (τ; 1, 0)) −1 is the partition function of half BPS states carrying charges (Q ′ , 0) =<br />

(Q − P, 0) with τ being conjugate to Q ′2 /2 = (Q − P ) 2 /2. Since (Q − P ) 2 /2 = (−2m + K + J)<br />

can take arbitrary integer values, the corresponding partition function is also given by η(τ) −24 .<br />

Thus we have near (ˇσ s + 2ˇv s ) = 0<br />

̂Φ(ˇρ, ˇσ s , ˇv s ) ∝<br />

{<br />

(2ˇv s + ˇσ s ) 2 η<br />

(<br />

ˇρ + 1 4 ˇσ s + ˇv s<br />

) 24<br />

η<br />

̂Φ given in (4.5.2.7) can be shown to satisfy this property.<br />

( ) 24 ˇσs<br />

+ O((2ˇv s + ˇσ s ) )}<br />

4<br />

4<br />

(4.5.2.30)<br />

φ m (τ; 1, 1) transforms as a modular form of weight 12 under τ → (α 1 τ + β 1 )/(γ 1 τ + δ 1 )<br />

with α 1 , β 1 , γ 1 , δ 1 ∈ Z, α 1 δ 1 −β 1 γ 1 = 1. On the other hand φ e (τ; 1, 0) transforms as a modular<br />

form of weight 12 under τ → (p 1 τ + q 1 )/(r 1 τ + s 1 ) with p 1 , q 1 , r 1 , s 1 ∈ Z, p 1 s 1 − q 1 r 1 = 1.<br />

Using (4.3.29), (4.3.30) and (4.5.2.14) we see that the the action of these transformations on<br />

the variables (ˇρ, ˇσ s , ˇv s ) may be represented by the symplectic matrices<br />

⎛<br />

⎞ ⎛<br />

α 1 (α 1 − 1)/2 β 1 0<br />

⎜ 0 1 0 0<br />

⎟<br />

⎝ γ 1 γ 1 /2 δ 1 0 ⎠ ,<br />

γ 1 /2 γ 1 /4 (δ 1 − 1)/2 1<br />

⎞<br />

1 (1 − p 1 )/2 q 1 −2q 1<br />

⎜ 0 p 1 −2q 1 4q 1<br />

⎝ 0 0 1 0<br />

0 r 1 /4 (1 − s 1 )/2 s 1<br />

⎟<br />

⎠ .<br />

(4.5.2.31)<br />

By comparing with the matrices given in (4.5.2.16) we see however that the transformations<br />

(4.5.2.31) generates symmetries of the full partition function only after we impose the additional<br />

constraints<br />

r 1 , γ 1 ∈ 4 Z . (4.5.2.32)<br />

Thus here we encounter a case where only a subset of the symmetries of the partition function<br />

near a pole is lifted to a full symmetry of the partition function. By examining the<br />

details carefully one discovers that in this case the pole comes from the first term in (4.5.2.7).<br />

Whereas this term displays the full symmetry given in (4.5.2.31), requiring that the other term<br />

also transforms covariantly under this symmetry generates the additional restrictions given in<br />

(4.5.2.32).<br />

Finally we turn to the constraint from black hole entropy. As in §4.5.1, in this case we<br />

have g(τ) = η(τ) 24 in (4.4.4). Thus (4.4.6) takes the form<br />

̂Φ(ˇρ, ˇσ, ˇv) ∝ (2v − ρ − σ) 10 {v 2 η(ρ) 24 η(σ) 24 + O(v 4 )} , (4.5.2.33)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!