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Lecture Notes for 120 - UCLA Department of Mathematics

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1.2. ARCLENGTH AND LINEAR MOTION 14<br />

This is easily shown to be independent <strong>of</strong> the parameter t as long as the reparametrization<br />

is in the same direction. One also easily checks that a curve on [a, b] is stationary<br />

if and only if its speed vanishes on [a, b]. Weusuallysuppresstheinterval<br />

and instead simply write L (q).<br />

Example 1.2.1. If q (t) =q 0 + v 0 t is a straight line, then its speed is constant<br />

|v 0 | and so the arclength over an interval [a, b] is |v 0 | (b a).<br />

Example 1.2.2. If q (t) =R (cos t, sin t)+c is a circle <strong>of</strong> radius R centered at<br />

c, thenthespeedisalsoconstantR and so again it becomes easy to calculate the<br />

arclength.<br />

Example 1.2.3. Consider the hyperbola x 2 y 2 =1. It consists <strong>of</strong> two components<br />

separated by the y-axis. The component with x>0 can be parametrized<br />

using hyperbolic functions q (t) = (cosh t, sinh t). The speed is<br />

ds p<br />

p<br />

dt = sinh 2 t + cosh 2 t = 2sinh 2 t +1= p cosh 2t<br />

While this is both a fairly simple curve and a not terribly difficult expression <strong>for</strong><br />

the speed it does not appear in any way easy to find the arclength.<br />

Definition 1.2.4. Acurveiscalledregular if it is never stationary, or in<br />

other words the speed is always positive. A curve is said to be parametrized by<br />

arclength if its speed is alway 1. Suchaparametrizationisalsocalledaunit speed<br />

parametrization.<br />

Lemma 1.2.5. A regular curve q (t) can be reparametrized by arclength.<br />

Pro<strong>of</strong>. If we have a reparametrization q (s) <strong>of</strong> q (t) with ds<br />

dt<br />

> 0 that has unit<br />

speed, then<br />

dq ds<br />

ds dt = dq<br />

dt = v<br />

so it follows that<br />

ds<br />

dt = dq = |v|<br />

dt<br />

must be the speed <strong>of</strong> q (t).<br />

This tells us that we should define the reparametrization s = s (t) as the antiderivative<br />

<strong>of</strong> the speed:<br />

ˆ t1<br />

dq<br />

s (t 1 )=s (t 0 )+ dt<br />

t 0<br />

dt<br />

It then follows that<br />

ds<br />

dt = dq > 0<br />

dt<br />

Thus it is also possible to find the inverse relationship t = t (s) and we can define<br />

the reparametrized curve as q (s) =q (s (t)) = q (t).<br />

This reparametrization depends on specifying an initial value s (t 0 ) at some<br />

specific parameter t 0 . For simplicity one <strong>of</strong>ten uses s (0) = 0 if that is at all<br />

reasonable.<br />

⇤<br />

To see that arclength really is related to our usual concept <strong>of</strong> distance we show:

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