Lecture Notes for 120 - UCLA Department of Mathematics
Lecture Notes for 120 - UCLA Department of Mathematics
Lecture Notes for 120 - UCLA Department of Mathematics
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8.2. RIEMANNIAN GEOMETRY 171<br />
This expression shows how certain third order partials might not commute since<br />
we have<br />
2 3<br />
@ 3 q<br />
@u i @u j @u k<br />
@ 3 q<br />
@u j @u i @u k = ⇥<br />
@q<br />
@u 1 ···<br />
@q<br />
@u n<br />
⇤ 6<br />
4<br />
But recall that since second order partials do commute we have<br />
@ 3 q<br />
@u i @u j @u k = @ 3 q<br />
@u i @u k @u j<br />
So we see that third order partials commute if and only if the Riemann curvature<br />
vanishes. This can be used to establish the difficult existence part <strong>of</strong> the next result.<br />
R 1 ijk<br />
.<br />
R n ijk<br />
Theorem 8.2.1. [Riemann] The Riemann curvature vanishes if and only if<br />
there are Cartesian coordinates around any point.<br />
Pro<strong>of</strong>. The easy direction is to assume that Cartesian coordinates exist. Certainly<br />
this shows that the curvatures vanish when we use Cartesian coordinates, but<br />
this does not guarantee that they also vanish in some arbitrary coordinate system.<br />
For that we need to figure out how the curvature terms change when we change<br />
coordinates. A long tedious calculation shows that if the new coordinates are called<br />
v i and the curvature in these coordinates ˜R l ijk , then<br />
˜R ijk l = @u↵ @u @u @v l<br />
@v i @v j @v k @u R ↵ .<br />
Thus we see that if the all curvatures vanish in one coordinate system, then they<br />
vanish in all coordinate systems.<br />
Conversely, to find Cartesian coordinates set up a system <strong>of</strong> differential equations<br />
@q<br />
@u i = U i<br />
@ ⇥ ⇤<br />
U1 ··· U<br />
@u i n = ⇥ ⇤<br />
U 1 ··· U n [ i]<br />
whose integrability conditions are a consequence <strong>of</strong> having vanishing curvature. ⇤<br />
7<br />
5