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plc karnaugh - 7.7<br />

5. Examine the truth table below <strong>and</strong> design the simplest ladder logic using a Karnaugh map.<br />

D<br />

E<br />

F<br />

G<br />

Y<br />

0<br />

0<br />

0<br />

0<br />

0<br />

0<br />

0<br />

0<br />

1<br />

1<br />

1<br />

1<br />

1<br />

1<br />

1<br />

1<br />

0<br />

0<br />

0<br />

0<br />

1<br />

1<br />

1<br />

1<br />

0<br />

0<br />

0<br />

0<br />

1<br />

1<br />

1<br />

1<br />

0<br />

0<br />

1<br />

1<br />

0<br />

0<br />

1<br />

1<br />

0<br />

0<br />

1<br />

1<br />

0<br />

0<br />

1<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

0<br />

0<br />

0<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

0<br />

1<br />

6. Find the simplest Boolean equation for the Karnaugh map below without using Boolean algebra<br />

to simplify it. Draw the ladder logic.<br />

ABC<br />

ABC<br />

ABC<br />

ABC<br />

ABC<br />

ABC<br />

ABC<br />

ABC<br />

DE<br />

1<br />

1<br />

0<br />

1<br />

0<br />

0<br />

0<br />

0<br />

DE<br />

1<br />

1<br />

0<br />

0<br />

0<br />

0<br />

0<br />

0<br />

DE<br />

1<br />

1<br />

0<br />

0<br />

0<br />

0<br />

0<br />

0<br />

DE<br />

1<br />

1<br />

0<br />

1<br />

0<br />

0<br />

0<br />

0<br />

7. Given the following truth table for inputs A, B, C <strong>and</strong> D <strong>and</strong> output X. Convert it to simplified

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