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TUTTE POLYNOMIAL OF AN INFINITE CLASS OF NANOSTAR DENDRIMERS<br />

Figure 2. Denderimer D[2].<br />

For example, let G be a tree with n vertices, then T(G, x, y) = x n -1 ,<br />

because all the edges in a tree are bridges. The dendrimer D[n] in Figure 2<br />

is a tree with 2×3 n+1 n 1<br />

2× 3 −2<br />

-1 vertices, thusT ( D[<br />

n],<br />

x,<br />

y)<br />

= x<br />

+<br />

.<br />

The Figure 1 has been constructed by joining six Ns[0] units to the<br />

hexagons in the outer layers, as detailed in Figures 3 and 4.<br />

Figure 3. Ns[0] and Ns[0]-H 1 +C 5 .<br />

Figure 4. Ns[1].<br />

6<br />

⎛ x −x<br />

⎞<br />

Lemma 1. Let H be a hexagon. Then T(D[H], x, y) =<br />

⎜ + y<br />

⎟.<br />

⎝ x−1<br />

⎠<br />

Proof. By using the formula of Tutte polynomial, we have:<br />

5<br />

T(D[H], x, y) = x + T(D[C<br />

5], x, y)<br />

= + +<br />

5 4<br />

x x T(D[C<br />

4<br />

], x, y)<br />

= + + +<br />

5 4 3<br />

x x x T(D[C<br />

3], x, y)<br />

6<br />

x − x<br />

= + y.<br />

x −1<br />

133

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