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OMEGA POLYNOMIAL FOR NANOSTRUCTURES DESIGNED BY (P 4 ) k Le OPERATIONS<br />

parameters are given in Table 3. Observe, in the dual pair, the face of<br />

parent becomes the vertex of transform and this interchanging operates<br />

also on the corresponding parameters: s 0 f 0 becomes d 0 v 0 , while the number<br />

of edges remains unchanged.<br />

Table 2. Platonic solid graph parameters<br />

Graph Vertices |v 0 | Degree d 0 Edges |e 0 | Ring folding s 0 Faces |f 0 |<br />

T 4 3 6 3 4<br />

C 8 3 12 4 6<br />

Oct 6 4 12 3 8<br />

Do 20 3 30 5 12<br />

Ico 12 5 30 3 20<br />

Table 3.Transforms of the Platonic solid graphs by Le(P 4 (M)) k )<br />

M Vertices |v 0 | Edges |e 0 | Faces |f 0 |<br />

T 12× 4 k<br />

18× 4 k<br />

k<br />

6× 4 + 2<br />

C 24× 4 k<br />

36× 4 k<br />

k<br />

12× 4 + 2<br />

Do 60× 4 k<br />

90× 4 k<br />

k<br />

30× 4 + 2<br />

Formula | v| = 4 k × s0f<br />

| | 3 4 k<br />

k<br />

e = × × e<br />

0<br />

0 | f | = 4 × e0<br />

+ 2<br />

Oct 24× 4 k<br />

36× 4 k<br />

k<br />

12× 4 + 2<br />

Ico 60× 4 k<br />

90× 4 k<br />

k<br />

30× 4 + 2<br />

Formula | v| = 4 k × d0v0<br />

| e| 3 4 k<br />

k<br />

= × × e<br />

| f | = 4 × e0<br />

+ 2<br />

Ring polynomial<br />

The ring polynomial for the graphs originating in trivalent Platonics<br />

is as follows:<br />

4<br />

0<br />

( )<br />

4 6<br />

( )<br />

8<br />

( )<br />

4 6<br />

( )<br />

8<br />

( ) ( )<br />

k a a<br />

R( Le(( P (T)) ), x) = 3× 4 x + 8x + 3× 4 − 6 x<br />

(5)<br />

k a a<br />

R( Le(( P (C)) ), x) = 6× 4 x + 8x + 6× 4 − 6 x (6)<br />

4<br />

4<br />

k a 4 6 a 8 10<br />

R( Le(( P (Do)) ), x) = 15× 4 x + 20 x + 15× 4 − 30 x + 12 x (7)<br />

Generalizing, for the graphs transformed from the trivalent Platonics,<br />

the formula for ring polynomial is of the form:<br />

2( k−1) 4 6<br />

( )<br />

k−1 k−1 k 8 2s0<br />

( s0f0× 2 (2 − 1) + e0(2 − 1) ) x + f0<br />

x<br />

RLe ( (( P( Gd ( :3))) ), x) = sf× 2 x + vx +<br />

k<br />

4 0 0 0 0<br />

Now, considering the relation between the dual pairs, for the trigonal<br />

Platonics we have:<br />

2( k−1) 4 6<br />

( )<br />

k−1 k−1 k 8 2d0<br />

( dv<br />

0 0× 2 (2 − 1) + e0(2 − 1) ) x + v0x<br />

RLe ( (( P( G( f :3))) ), x) = dv× 2 x + fx +<br />

k<br />

4 0 0 0 0<br />

(8)<br />

(9)<br />

229

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