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SPICE-Simulation using LTspice IV

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11.2. The Step Up Converter<br />

The schematic shows a +12V power supply , followed by an inductance with L = 100mH and the obligatory series<br />

resistor of 1.<br />

The Power-MOSFET acts as an electronic switch between R1 and D1 to connect this node to ground for a<br />

definite time.<br />

When switched ON, current flows from the power supply through the inductor and its series resistor to ground and<br />

rises linearly (...this is true, when the voltage across an inductor is constant) .<br />

So more and more magnetic energy is stored in the inductor and this can be calculated from:<br />

1<br />

E = • L I<br />

2<br />

2<br />

•<br />

When the FET is switched OFF, this energy cannot dissipate suddenly and the inductor’s current cannot switch<br />

rapidly (….this would cause a nearly infinite induced voltage...) and so stays at the same value.<br />

That means that the inductor current now flows to the right hand side, switches ON the schottky diode, charges<br />

the output capacitor and flows through the output resistor R2. When the gate of the MOSFET is fed with a square<br />

wave voltage, the output voltage rises until a “balance” is reached between picked-up-energy (by the Inductor)<br />

and the energy delivered to the output resistor R2.<br />

Important: the amplitude of the output voltage is the sum of supply voltage +12V and the inductors<br />

voltage!<br />

This means that the output voltage of this circuit will<br />

always be higher than the supply voltage!<br />

Now draw the schematic and feed the gate with a symmetric square wave voltage (frequency = 1 kHz / (Vmax) =<br />

+15V / Vmin = -15V). Choose a simulation time from 0.....50ms. Show the gate voltage and the output voltage.<br />

71

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