tors actuators - Norgren Pneumatics. Motion Control Equipment ...
tors actuators - Norgren Pneumatics. Motion Control Equipment ...
tors actuators - Norgren Pneumatics. Motion Control Equipment ...
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Cushioning Performance<br />
The dynamic energy of a LINTRA ® cylinder is caused by direct or partial external loads<br />
which must be absorbed by pneumatic cushioning.<br />
The cushioning ability depends to a large extent on the pneumatic circuit (e. g. counter<br />
pressure, pre-exhaust). The values given in the diagram were tested with an operation<br />
pressure of 87 psi (6 bar) using a 5/2 control valve. When installed horizontally, depending<br />
upon the speed, dynamic energy can be absorbed by the cylinder. Whenever the values<br />
given in the diagram are exceeded, the transported mass must be cushioned by additional<br />
shock absorbers. These have to be located at the center of gravity of the mass.<br />
lb. (kg)<br />
2204 (1000)<br />
1763 (800)<br />
1300 (600)<br />
882 (400)<br />
441 (200)<br />
176 (80)<br />
132 (60)<br />
88 (40)<br />
44 (20)<br />
22 (10)<br />
18 (8)<br />
13 (6)<br />
8.8 (4)<br />
4.4 (2)<br />
2.2 (1)<br />
C/146000, C/146100, C/146200<br />
16”<br />
(0.4)<br />
31”<br />
(0.8)<br />
47”<br />
(1.2)<br />
63”<br />
(1.6)<br />
Ø 80<br />
Ø 63<br />
50<br />
Ø 40<br />
Ø 32<br />
Ø 25<br />
Ø 20<br />
Ø 16<br />
79”<br />
(2.0)<br />
V<br />
inches /s<br />
(m / s)<br />
ACTUATORS<br />
Cylinder deflection<br />
2248<br />
(10000)<br />
1124<br />
(5000)<br />
Deflection due to external forces<br />
f1= 0.04” (1 mm)<br />
224<br />
(1000)<br />
112<br />
(500)<br />
22.5<br />
(100)<br />
2.25<br />
(10)<br />
0.22<br />
(1) 0 39” 6.6’<br />
(1000) (2000)<br />
72”<br />
(1830)<br />
9.8’<br />
(3000)<br />
13’<br />
(4000)<br />
16.4’<br />
(5000)<br />
inches (mm)<br />
Support length<br />
Example:<br />
Cylinder Ø 32 mm, stroke length 11' (3500 mm), external load<br />
45 lbf. (200 N) and a deflection about 0.04 (1 mm).<br />
Maximum distance between supports = 6' (1830 mm) (see<br />
diagrams).<br />
Therefore an additional support is required.<br />
Ø80<br />
Ø63<br />
Ø50<br />
Ø40<br />
Ø32<br />
Ø25<br />
Ø20<br />
Ø16<br />
19.6’<br />
(6000)<br />
Deflection due to cylinder weight<br />
f<br />
0.004” (0.1)<br />
0<br />
2<br />
0.08” (2)<br />
0.04” (1)<br />
0.02” (0.4)<br />
inches (mm)<br />
0.04<br />
(0.9)<br />
3.2’<br />
(1000)<br />
6.5’<br />
(2000)<br />
9.8’<br />
(3000)<br />
13’<br />
(4000)<br />
16.4’<br />
(5000)<br />
Example:<br />
Cylinder Ø 40 mm. external force 40 lbf (180 N),<br />
distance between supports 10' (3000 mm)<br />
Required: total deflection<br />
1. Deflection due to external force (f1)<br />
see Diagram 1 (1mm/100 N) · 40 lbf (180 N)<br />
2. Deflection due to cylinder weight diagram 2<br />
Total deflection:<br />
Max. permitted deflection (f1 + f2)<br />
A deflection of more than 0.12" (3 mm)<br />
is not permitted.<br />
Support length<br />
19.7’<br />
(6000)<br />
ft.<br />
(mm)<br />
0.07"(1.8 mm)<br />
+ 0.04"(0.9 mm)<br />
0.2" (2.7 mm)<br />
< 0.04"(1 mm)<br />
39"(1000 mm) Stroke<br />
<strong>Norgren</strong>.com/usa – 303.794.2611 – help@amer.norgren.com<br />
ACT-105
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