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advanced drainage system - Polypipe

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General Structural Design 3.2<br />

3.2.3 Design Example<br />

Product<br />

Application<br />

Burial Depth<br />

Native Soil<br />

Ovalization,<br />

600mm Ø Ridgisewer (SN4)<br />

Adoptable sewer beneath an A-road<br />

3.0m to pipe crown<br />

Very loose gravel<br />

Kx [(DLPe)+Ps]<br />

=<br />

D (8EI/D 3 )+ (0.061E’)<br />

Calculation of soil modulus adjustment factor, CL<br />

Pipe O.D., BC<br />

= 672mm<br />

Trench width, Bd<br />

= BC + 300mm<br />

= 972mm<br />

(Table 3.2.6)<br />

Assuming native soil is a Very Loose Gravel<br />

Native Soil Modulus, E’3 = 3 MN/m 2 ,<br />

Pe = 19.6 x 3.0<br />

= 58.8 kN/m 2<br />

CL =<br />

0.985+[0.544(972/672)]<br />

[1.985-0.456(972/672)](10/3)-[1-(972/672)]<br />

No soil density data available, therefore 19.6 kN/m 3<br />

assumed. (Clause NA. 6.3 BS EN 1295-1)<br />

Ps = 26 kN/m 2 (Figure 3.2.4)<br />

DL = 1.0 (Table 3.2.5)<br />

Kx = 0.083 (Table 3.2.5)<br />

EI/D 3 = 1.74 kN/m 2 (<strong>Polypipe</strong> Civils Technical Data)<br />

(Table 2.4.2)<br />

Overall Soil Modulus, E’ = E’2 CL<br />

CL = 0.3642<br />

Overall Soil Modulus, E’ = 10 MN/m 2 x 0.3642<br />

= 3.642 MN/m 2<br />

0.083[(1.0 x 58.8)+26.0]<br />

Ovalization, =<br />

D (8 x 1.74)+(0.061 x 3642)<br />

= 0.0298<br />

Deflection, = 0.0298 x D<br />

= 0.0298 x 0.672m = 0.020<br />

(Table 3.2.5)<br />

(Class S1 - Gravel (single size) )<br />

Bed & surround soil modulus, E’2 = 10 MN/m 2<br />

Percentage Deflection = (0.020 / 0.587) x 100<br />

= 3.41% ≤ 6.0<br />

Therefore acceptable<br />

Cover depth is >1.5m, therefore buckling check with<br />

soil support only is required.<br />

3.2.4 Buckling check with soil support<br />

Factor of Safety, FS =<br />

1<br />

(Pe/Pcrl)+[(Ps+Pv)/Pcrs]<br />

Where: Pcrl = 0.6(1.74) 0.33 .(3642) 0.67 kN/m 2<br />

= 0.6 x 1.201 x 243.275 kN/m 2<br />

= 175.30 kN/m 2<br />

Pcrs = 0.6(7.83) 0.33 .(3642) 0.67 kN/m 2<br />

= 0.6 x 1.972 x 243.275 kN/m 2<br />

= 287.84 kN/m 2<br />

Factor of Safety, FS = 1/0.426<br />

= 2.34 ≥ 2.0 Therefore adequate<br />

56

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