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enumeration of the number of spanning trees in some ... - Toubkal

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76CHAPTER 4.NEW METHODS TO COMPUTE THE NUMBER OF SPANNINGTREES OF PLANAR MAPS4.3.3 Count<strong>in</strong>g <strong>the</strong> <strong>number</strong> <strong>of</strong> <strong>spann<strong>in</strong>g</strong> <strong>trees</strong> <strong>in</strong> a map <strong>of</strong> typeC= C 1 : C 2Now, we are <strong>in</strong>terested <strong>in</strong> <strong>the</strong> maps <strong>of</strong> type C= C 1 : C 2 , C is a map such that if a pathconnects a vertex v k <strong>of</strong> C 1 and a vertex v l <strong>of</strong> C 2 must pass through v 1 or v 2 ; C 1 and C 2have two common vertices v 1 , v 2 (see Figure 4.10).Figure 4.10: A map C= C 1 : C 2Example 4.3.23 Here is an example <strong>of</strong> this type <strong>of</strong> maps (see Figure 4.11):Figure 4.11: An example <strong>of</strong> map C= C 1 : C 2Property 4.3.24 Let C be a map <strong>of</strong> type C= C 1 : C 2- C 1 and C 2 have two common vertices v 1 , v 2 and a common face (<strong>the</strong> external face).- V C =V C1 +V C2 -2, E C =E C1 +E C2 and F C =F C1 +F C2 .- A path that connects a vertex <strong>of</strong> C 1 and a vertex <strong>of</strong> C 2 must pass through v 1 or v 2 .- If we remove <strong>the</strong> two vertices v 1 and v 2 <strong>of</strong> <strong>the</strong> map C, <strong>the</strong> result<strong>in</strong>g map is not connected.Example 4.3.25 Here is an example <strong>of</strong> maps C= C 1 : C 2 , C 1 , C 2 , C 1 .v 1 v 2 and C 2 .v 1 v 2 (seeFigure. 4.12).

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