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IBM 5280 Distributed Data System - Index of

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Binary Double Register Subtract with a Base Displacement Address (-=)So.urce:Object:l... __ B_6_-,t __;+'--oI!J""11~5 --@""--¥~23~1_1+1-~JDB DD IID Result/factor 1: The address <strong>of</strong> the binary register that contains factor 1and will contain the result <strong>of</strong> this instruction.fJ Bit 15:o = Length <strong>of</strong> factor 2 is 2.1 = Length <strong>of</strong> factor 2 is 1.D Base address register: The address <strong>of</strong> the binary register that contains thebase address.II Address bit:0= BRa contains a 16-bit address.1 = BRa(4) contains a 20-bit address <strong>of</strong> a storage location outside thepartition.II Factor 2 displacement: The number <strong>of</strong> bytes (hex OO-FF) from the base addresswhere factor 2 is stored.The factor 2 displacement is subtracted from the contents <strong>of</strong> the base register, thenthe data at the resulting address is logically subtracted from factor 1.Object Code Instruction Format 263

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