Final Chemistry Notebook

Find Molecular Mass 1- 10
1. NaBr
NA 1 * 23= 23
Br 1 * 80= 80 = 103 g/,ol
2. PbSO4
3. Zn(C2H3O2)2
4. Na3PO4
Pb 1* 207= 207
S 1*32= 32
O 4*16 = 64 = 303g/mol
Zn 1 * 65 =65
C 4* 12 = 48
H 6* 1 = 6
O 4 * 16 = 64 = 183g/mol
Na 3* 23= 69
P 1* 31= 31
O 4* 16 =64 = 164g/mol
5. (NH4)2CO3
6. Glucose
C H O
6 12 6
7. Iron(II) Phosphate
N 2* 14=28
H 8* 1=8
C 1* 12=12
O 3* 16= 48 = 96 g/mol
C 6 * 12= 72
H 12 * 1= 12
O 6 * 16 = 96 = 180g/mol
Fe 3*56=168
P 2 * 31=62
O 8*16=128 = 358 g/mol
Fe (PO )
3
4 2
8. Ammonium Sulfide
N 2* 14= 28
(NH 4) 2S
H 8* 1= 8
S 1* 32=32 = 68 g/mol
9. Calcium Hydroxide
10. Silver(I) Fluoride
Ca(OH)2
Ca 1* 40= 40
O 2*16= 32
H 2* 1=2 = 74g/mol
AgF
Ag 1*108= 108
F 1*19=19 = 127g/mol
11. How many moles is 51g of NaBr?
12. How many moles is 60g of PbSO4?
13. How many moles is 150g of Zn(C2H3O2)2?
51g/mol NaBr
60g/mol PbSo
4
1 mol NaBr
103g/mol NaBr
1 mol PbSO
4
303g/mol PbSO4
= 51 mol
= 103
= .495 = .50 mol NaBr
= 60 mol
= .19801 =. 20 mol PbSO
=303
150g/mol Zn(C 2H 3O 2
) 2 1 mole Zn(C 2 H 3 O 2 ) 2 = 150 mol
183g/mol Zn(C H O ) = 183
= .8196 = .82 mol Zn(C H O )
2 3 2 3 2
2
2
2
4
14. How many moles is 578g of Na3PO4?
578g/mol Na 3PO
4
1mol Na
3
PO 4
164g/mol Na PO
= 578
= 164
= 3.5243 = 3.5 mol Na PO
3 4
15. How many moles is 500g of (NH4)2CO3?
500g/mol (NH ) CO
1 mol (NH ) CO
4 2 3 4 2 3
96g/mol (NH ) CO
4 2
3
= 5.2088 = 5.2 mol (NH ) CO
4
2 3
1. 103 g/mol 6. 180 g/mol 11. .50 mol
2. 303 g/mol 7. 358 g/mol 12. .20 mol
3. 74 g/mol 8. 68 g/mol 13. 2.0 mol
4. 164 g/mol 9. 183 g/mol 14. 3.5 mol
5. 96 g/mol 10. 127 g/mol 15. 5.2 mol
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