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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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!QP2\ = J [x2 - ~(X 1 + X2)] 2 + [y2- ~(Y l + Y2)] 2 + [z2 - ~ (z1 + z2)) 2<br />

SECTION 12.1 THREE-DIMENSIONAL COORDINATE SYSTEMS 0 113<br />

= (~x2- ~ x1) 2 + ( h2- ~ ·yt) 2 + (tz2 - ~z1 ) 2 = J G) 2 [(x2- xd + (y2 - yl) 2 + (z2 - z1) 2 )<br />

.= ~J(x2 - xd + (y2- y1) 2 + (z2- zd = ~ \P1P2\<br />

So Q is inde<strong>ed</strong> the midpoint of P 1P2.<br />

(b) By part (a), the midpoints of sides AB, B C and C A are P1 ( -~, 1, 4), P2 (1, ~. 5) and P3 (~ , ~, 4). (Re ~all that a m<strong>ed</strong>ian<br />

of a triangle is a line segment from a vertex to the midpoint of the opposite side.) Then the lengths of the m<strong>ed</strong>ians are:<br />

IAP2\ = Jo 2 + (~ - 2) 2 + (5 - 3) 2 = jf+4 = -fj = ~<br />

\BP3\ = J (~ + 2) 2 + (~) 2 + (4- 5) 2 = J¥ + * + 1 = J2j = ~JW<br />

\CP1\ = J (-~- 4) 2 + (1 :__ 1} 2 + (4- 5? = J¥ + 1 = ~.J85<br />

21 . (a) Since the sphere touches the xy-plan.e, its radius is the distance from its center, (2, -3, 6), to the xy-plane, namely 6.<br />

Therefore r = 6 and an equation of the sphere is (x- 2? + (y + 3? + (z - 6? = 6 2 = 36.<br />

(b) The radius of this sphere is the distance from its center (2, - 3, 6) to the yz-plane, which is 2. Therefore, an equation is<br />

(~- 2) 2 + (y + 3) 2 + (z - 6) 2 = 4.<br />

(c) Here the radius is the distance from the center (2, - 3, G) to the xz-plane, which is 3. Therefore, an equation is<br />

(x- 2) 2 + (y + 3) 2 + (z- 6} 2 = 9.<br />

23. The equation x = 5 represents a plane parallel to the yz-plane and 5 units in front of it.<br />

25. The inequality y < 8 represents a half-space consisting of all points to the left of the plane y = 8.<br />

27. The inequality 0 ~ z ~ 6 represents all points on or between the horizontal planes z = 0 (the xy-plane) and z = 6.<br />

29. Because z = - 1, all points in the region must lie in the horizontal plane ~ = -1. In addition, x 2 + y 2 = 4, so the region<br />

consists of all points that lie on a circle with radius 2 and center on the z-axis that is contain<strong>ed</strong> in the plane z = -1.<br />

31. The inequality x 2 + y 2 + z 2 ~ 3 is equivalent to jx 2 + y 2 + z 2 ~ J3, so the region consists of those points whose distance<br />

from the origin is at most V3. This is the set of all points on or inside the sphere with radius ../3 and center (0, 0 , 0).<br />

33. Here x 2 + z 2 ~ 9 or equiva lently Jx2 + z 2 ~ 3 which describes the set of all points in JR 3 whose distance from they-axis is<br />

at most 3. Thus, the inequality represents the region consisting of all points on or inside a circular cylinder of radius 3 with<br />

axis the y-axis.<br />

35. This describes all points whose x-coordinate is between 0 and 5, that is, 0 < x < 5.<br />

37. This describes a region all of whose points have a distance to the origin which is greater than r, but smaller than R. So<br />

inequalities describing the region are r < jx 2 + y 2 + z 2 < R, or r 2 < x 2 -1- y 2 + z 2 < R 2 .<br />

@ 2012 Ccngugc l earnlnu. All R i~lu s RescrvcU. May nut be scann<strong>ed</strong>, copit."t.l. or duplicat<strong>ed</strong>, or poSicd ton public\)' :~cccss i btc website. in whoJc or in part.

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