31.03.2019 Views

Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

124 0 CHAPTER 12 VECTORS AND THE GEOMETRY OF SPACE<br />

j k<br />

5. ax b = 1 - 1 -1<br />

= ,-~ -~ li 11 - 1, . 11<br />

1 1 J + 1 -~ lk<br />

1<br />

1 2 2 2<br />

2 1 2<br />

Now {ax b)· a= {~ i-j + ~ k ) · (i-j - k) = ~ + 1- ~<br />

~ 0 and<br />

(a x b ) · b = { ~ i - j + ~ k) · G i + j + ~ k) = ~ - 1 + ~ = 0, so a x b is orthogonal to both a and b .<br />

j k<br />

= 1 1/t I<br />

i -I t 1/t I· + I t<br />

7. a x b = t 1 1/t<br />

1 I k<br />

t21 t21 J t<br />

e 2 t2<br />

t 2 1<br />

= (1 - t) i - (t- t) j + (t 3 - t 2 ) k = (1 - t) i + (t 3 - t 2 ) k<br />

Since {a X b). a = (1 -t,O,t 3 - t2). (t, 1, 1/t) = t-e +0 +t 2 - t = 0, a X b is orthogonal to a.<br />

Since (a x b ) · b = ( 1 - t, 0, t 3 - t 2 ) • ( t 2 , t 2 , 1) = t 2 - t 3 + 0 + t 3 - t 2 = 0, a x b is orthogonal to b .<br />

9. According to the discussion prec<strong>ed</strong>in.g Theorem II, i x "j = k, so (i x j ) x k = k x k = 0 [by Example 2).<br />

11. (j - k) X (k- i) = (j - k) X k + (j - k) .X ( - i)<br />

= j X k + (- k) X k + j X (-i) + (-k) X (- i)<br />

= (j X k ) + (-1){k X k) + (- 1)(j Xi)+ (-1) 2 (k X i)<br />

= i + (-1) 0 + (-1)(- k) + J = i + j + k<br />

by Property 3 of Theorem I I<br />

by Property 4 of Theorem 11<br />

by Property 2 of Theorem I 1<br />

by Example 2 and<br />

the discussion prece<strong>ed</strong>ing Theorem II<br />

13. (a) Since b x cis a vector, the dot product a· (b x c) is meaningful and is a scalar.<br />

(b) b ·cis a scalar, so a x (b ·c) is mean<strong>ingles</strong>s, as the cross product is defin<strong>ed</strong> only for two vectors.<br />

(c) Since b x cis a vector, the cross'product a x (b x c) is meaningful and results in another vector.<br />

(d) b · cis a scalar, so the dot product a · (b ·c) is mean<strong>ingles</strong>s, as the dot product is defin<strong>ed</strong> only for two vectors.<br />

(e) Since (a . b ) and ( c . d) are both scalars, the cross product (a . b ) X ( c . d) is mean<strong>ingles</strong>s.<br />

(f) a x band c x d arc both vectors, so the dot product (ax b)· (c x d ) is meaningful and is a scalar.<br />

15. If we sketch u an~ v starting from the same initial point, we see.that the<br />

angle between them is 60°. Using Theorem 9, we have<br />

lu x vi = lullvl sin 0 = {12)(16) sin 60° = 192 · v; = 96 v'3.<br />

By the right-hand rule, u x v is direct<strong>ed</strong> into the page. .<br />

v<br />

© 2012 Ccng.age Learning. All Rights Reserv<strong>ed</strong>. May nol be sc.::um<strong>ed</strong>. copit."ll, or duplicat<strong>ed</strong>, or polo1ctl too publicly accessible website. in whole or in part.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!