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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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SECTION 11.10 TAYLOR AND MACLAURIN SERIES 0 85<br />

. lan+l l r l( - lt+2(x~2)"+ 1 n2" 1- li l(- l)(x-2)n,_ r . ( n) lx-21<br />

J~ ~ = n~ (n + 1) 2n+l . ( - 1)"+ 1 (x- 2)" - ,._n;., (n + 1)2 - ":~ n + 1 - 2-<br />

= lx - 2 1 < 1 for convergence, so lx - 21 < 2 and R = 2.<br />

2<br />

17.<br />

n t

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