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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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10 D PARAMETRIC EQUATIONS AND POLAR COORDINATES<br />

10.1 Curves Defin<strong>ed</strong> by Parametric Equations<br />

1. X= t 2 + t, y = t 2 - t, -2 S t S 2<br />

t - 2 - 1 0 l 2<br />

X 2 0 0 2 6<br />

y 6 2 0 0 2<br />

y<br />

t = - 2<br />

(2, 6)<br />

X<br />

3. x = cos 2 t, y = 1 - sin t, 0 S t S 7r /2<br />

t 0 7r/6 7r/3 7r/ 2<br />

X 1 3/ 4 1/ 4 0<br />

y 1 1/ 2 1 - 1 ~ 0.13 0<br />

y<br />

r=JI.<br />

6<br />

t=O<br />

(1, 1)<br />

X<br />

5. X = 3 - 4t, y = 2 - 3t<br />

(a)<br />

t - 1 0 1 2<br />

X 7 3 -1 - 5<br />

y 5 2 -1 - 4<br />

y<br />

(7, S)<br />

t= -1<br />

(3, 2)<br />

t = O<br />

X<br />

(b) X= 3 - 4t =} 4t = -X + 3 =} t = -~ X +~ ' SO<br />

y = 2 - 3t = 2 - 3(- ~x + ~ ) = 2 +~ X - £ =} y =~X - ~<br />

(-5, - 4)<br />

1=2<br />

1. x = 1 - e, v = t - 2, - 2 s t s 2<br />

(- 3, 0)<br />

t=2<br />

y<br />

(a)<br />

t - 2 - 1 0 1 2<br />

X -3 0 1 0 -3<br />

y - 4 -3 - 2 - 1 0<br />

X<br />

(1, - 2)<br />

t= O<br />

(b) y = t - 2 =} t = y + 2, SO X= 1 - t 2 = 1 - (y + 2? =}<br />

x = - (y + 2) 2 + 1, or x =:= - y 2 - 4y -e 3, with - 4 S y S 0<br />

© 2012 Certgagc Learning. Ail Rights Reserv<strong>ed</strong>. May not be scann<strong>ed</strong>, copi<strong>ed</strong>, o r duplicat<strong>ed</strong>, o r post<strong>ed</strong> to a publicly accessible website, in ''•hole or in part.

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