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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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CHAPTER 10 REVIEW 0 37<br />

EXERCISES<br />

1. X = t 2 + 4t, y = 2 - t, - 4 ~ t ~ 1. ~ = 2 - y, SO<br />

y<br />

X = {2 - y) 2 + 4{2- y) = 4- 4y + y 2 + B- 4y = y 2 - By+ 12 {::}<br />

x + 4 = y 2 -<br />

By+ 16 = (y - 4) 2 . This is part of a parabola with vertex<br />

( -4, 4), opening to the right.<br />

X<br />

3. y = sec() = ~() = .! . Since 0 ~ () ~ 1r /2, 0 < x ~ 1 and y ;::: 1.<br />

COS X<br />

This is part of the hyperbola y = 1/x.<br />

y<br />

\ ,1,1),0-0<br />

0<br />

5. Three different sets of parametric equations for the curve y = -IX are<br />

(i) X = t, y = Vt<br />

(ii) X = t 4 , y = t 2<br />

(iii) x = tan 2 t, y = tan t, 0 ~ t < 1r /2<br />

There are many other sets of equations that also give this curve.<br />

7. (a) The Cartesian coordinates are x = 4 cos 2 ; = 4 (- ~) = -2 and<br />

y = 4sin ;,. = 4( 4) = 2 J3, that is, the point ( - 2,2 J3).<br />

(b) Give~ x = - 3 and y= 3, we haver = J( -3) 2 + 3 2 = JIB = 3 v'2. Also, tan() = ~ '* tan() = ~ , and since<br />

3<br />

( -3, 3) is in the second quadrant,(}= ' 3 4 ". Thus, one set of polar coordinates for ( -3, 3) is (3 V2, 3 ,;'"), and two others are<br />

(3 '2 1 111") and (- 3 '2 7 ,.)<br />

y ~, 4 v. .L.i, 4 .<br />

9. r = 1 - cosO. This cardioid is<br />

symmetric about the polar axis.<br />

r<br />

2<br />

(2, 7T)<br />

7T 27T 0<br />

® 2012 Censagcl..eaming. All Rights Rcscn"

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