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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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M xv = I~1f I: I:2 6 - 3 r 2 (zK) r dz dr d() = J( I~ 1f<br />

SECTION 15.8 TRIPLE INTEGRALS IN CYLINDRICAL COORDINATES 0 279<br />

I: r [ ~ z 2 ) ; :~~- 3 ,. 2 dr d()<br />

=if I 0<br />

2 " I: r((36- 3r 2 ) 2 - r 4 ) dr d() = if I~-:r d8 I 0<br />

3<br />

(8r<br />

5 - 216r 3 + 1296r) dr<br />

- K (27r) [.!!.r6 - 216 r4 + 1296 r2] 3 = 11" !((2430) = 243011" J(<br />

-2 6 4 ~ 0 .<br />

(<br />

- __) ( M 11z Mxz M:xv ) (O O 2430rr<br />

Thus x, y, z = --,--,--. = , I

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