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Exercicios resolvidos James Stewart vol. 2 7ª ed - ingles

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SECTION 14.3 PARTIAL DERIVATIVES 0 195<br />

sin(xy)<br />

43. f(x, y) = xy<br />

{<br />

1<br />

if (x, y) :f. (0, 0)<br />

if (x, y) = (0, 0)<br />

From the graph, it appears that f is continuous everywhere. We know<br />

xy is continuous on R 2 .and sin t is continuous everywhere, so<br />

.<br />

( )<br />

R2 d sin(:cy) . . R2<br />

sin xy is contmuous on an --- IS contmuous on<br />

x y<br />

-1<br />

except possibly where x y = 0. To show that f is continuous at those points, consider any point (a, b) in R 2 where ab = 0.<br />

Because x y is continuous, x y --+ ab == 6 as {x, y ) --+ (a, b). If we lett= x y, then t--+ 0 as (x, y) --+ (a, b) and<br />

lim sin(xy). = Jim sin(t) = l by Equation 2.4.2 [ET 3.3.2). Thus lim f (x, y) = f(a, b) and f is continuous<br />

(x,y)-(a,b) x y t-o t (:z:,y)-(a,b)<br />

on R 2 •<br />

45. since Jx - aJ 2 = lxl 2 + Jal 2 . - 2JxJ ial cos O ~ Jxl 2 + Jal 2 - 2Jx.JJal = (lxJ -Ial) 2 , we have llxl - lall $ lx- aJ. Let<br />

t > 0 be given and set o = t. Then ifO < lx - al < o, llxJ- IaJI $ Jx - aJ < o = t . Hence limx-a Jxl = Jal and<br />

f (x) = Jxl is continuous on R".<br />

14.3 Partial Derivatives<br />

1. (a) 8T I 8x represents the rate of change ofT when we fi x y and t and consider T as a function of the single variable x, which<br />

describes how quickly the temperature changes when longitude changes but latitude and time are constant. 8T 18y<br />

represents the rate of change of T when we fix x and t and consider T as a function of.y, which describes how quickly the<br />

temperature changes when latitude changes but longitude and time are constant. 8T I 8t represents the rate of change ofT<br />

when we fix x andy and consider T as a function oft , which describes how quickly the temperature changes over time for<br />

a constant longitude and latitude.<br />

(b) f .,(158, 21, 9t represents the rate of change of temperature at longitude 158°W, latitude 21 °N at 9:00AM when only<br />

longitude varies. Since the air is warmer to the west than to the east, increasing longitude results in an increas<strong>ed</strong> air<br />

temperature, so we would expect .f:r: (158, 21, 9) to be positive. / 11 (158, 21 , 9) represents the rate of change oftemperature<br />

at the same time and location when only latitude varies. Since the air is warmer to the south and cooler to the north,<br />

increasing latitude results in a decreas<strong>ed</strong> air temperature, so we would expect / 11 (158, 21, 9) to be negative. ft(158, 21, 9)<br />

represents the rate of change of temperature at the same time and location when onJy time varies. Since typically air<br />

temperature increases from the morning to the afternoon as the sun warms it, we would expect f t(158, 21, 9) to be<br />

positive.<br />

3. a By De tlon<br />

. 4<br />

,<br />

f ( 15 30) lim f(- 15 + h,30) - f(- 15,30) h' h . b 'd . h<br />

T - , = h , w 1c we can approx1mate y cons1 ermg = 5<br />

() fini<br />

h-0<br />

and h = -5 and using the values given in the table:<br />

© 201 2 Ccngoge J.cnming. All Righ t" Rt:scr,.cd. May not~ .sc

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