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240 Chapter 6 IMPLEMENTATION OF DISCRETE-TIME FILTERS<br />

FIGURE 6.18<br />

All-zero lattice filter<br />

x(n), then the output of the (M − 1) stage lattice filter corresponds to<br />

the output of an (M − 1) order FIR filter; that is,<br />

f 0 (n) =g 0 (n) =K 0 x(n)<br />

y(n) =f M−1 (n)<br />

If the FIR filter is given by the direct form<br />

H(z) =<br />

M−1<br />

∑<br />

m=0<br />

M−1<br />

∑<br />

b m z −m = b 0<br />

(1+<br />

m=1<br />

)<br />

b m<br />

z −m<br />

b 0<br />

(6.17)<br />

(6.18)<br />

and if we denote the polynomial A M−1 (z) by<br />

A M−1 (z) =<br />

(<br />

1+<br />

M−1<br />

∑<br />

m=1<br />

α M−1 (m)z −m )<br />

; (6.19)<br />

α M−1 (m) = b m<br />

b 0<br />

,m=1,...,M − 1<br />

then the lattice filter coefficients {K m } can be obtained by the following<br />

recursive algorithm [23]:<br />

K 0 = b 0<br />

K M−1 = α M−1 (M − 1)<br />

J m (z) =z −m A m<br />

(<br />

z<br />

−1 ) ; m = M − 1,...,1<br />

A m−1 (z) = A m(z) − K m J m (z)<br />

1 − Km<br />

2 , m = M − 1,...,1<br />

K m = α m (m), m = M − 2,...,1<br />

(6.20)<br />

Note that this algorithm will fail if |K m | =1for any m =1,...,M − 1.<br />

Clearly, this condition is satisfied by linear-phase FIR filters since<br />

∣ b 0 = |b M−1 |⇒|K M−1 | = |α M−1 (M − 1)| =<br />

b M−1 ∣∣∣<br />

∣ =1<br />

b 0<br />

Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).<br />

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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