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Properties of Linear-phase FIR Filters 311<br />

Magnitude Response<br />

Amplitude Response<br />

|H|<br />

Hr<br />

0<br />

0<br />

0 2/3 1<br />

frequency in π units<br />

0 2/3 1<br />

frequency in π units<br />

Piecewise Linear Phase Response<br />

Linear Phase Response<br />

angle in π units<br />

2/3<br />

0<br />

−2/3<br />

angle in π units<br />

0<br />

−2/3<br />

0 2/3 1<br />

frequency in π units<br />

0 2/3 1<br />

frequency in π units<br />

FIGURE 7.2 Frequency responses in Example 7.3<br />

Type-1 linear-phase FIR filter: Symmetrical impulse response,<br />

M odd In this case β =0,α =(M − 1)/2 isaninteger, and h(n) =<br />

h(M − 1 − n), 0 ≤ n ≤ M − 1. Then we can show (see Problem P7.2)<br />

that<br />

⎡<br />

⎤<br />

(M−1)/2<br />

∑<br />

H(e jω )= ⎣ a(n) cos ωn⎦ e −jω(M−1)/2 (7.6)<br />

n=0<br />

where sequence a(n) isobtained from h(n) as<br />

( ) M − 1<br />

a(0) = h<br />

: the middle sample<br />

2<br />

( )<br />

M − 1<br />

a(n) =2h − n , 1 ≤ n ≤ M − 3<br />

2<br />

2<br />

Comparing (7.5) with (7.6), we have<br />

H r (ω) =<br />

(M−1)/2<br />

∑<br />

n=0<br />

(7.7)<br />

a(n) cos ωn (7.8)<br />

Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).<br />

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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