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FIR Filter Structures for Sampling Rate Conversion 527<br />

x(n)<br />

p 0 (n)<br />

y(m)<br />

Rate: F y = F x<br />

D<br />

p 1 (n)<br />

p I − 1 (n)<br />

FIGURE 9.38<br />

Decimation by use of polyphase filters<br />

Note that p 0(n) =h(2n) and p 1(n) =h(2n + 1). Hence one filter consists of<br />

the even-numbered samples of h(n), and the other filter consists of the oddnumbered<br />

samples of h(n).<br />

□<br />

□ EXAMPLE 9.18 For the interpolation filter designed in Example 9.8, determine the polyphase<br />

filter coefficients {p k (n)} in terms of the filter coefficients {h(n)}.<br />

Solution<br />

The polyphase filters obtained from h(n) have impulse responses<br />

p k (n) =h(5n + k) k =0, 1, 2, 3, 4<br />

Consequently, each filter has length 6.<br />

□<br />

9.6.3 TIME-VARIANT FILTER STRUCTURES<br />

Having described the filter implementation for a decimator and an interpolator,<br />

let us now consider the general problem of sampling rate conversion<br />

by the factor I/D. Inthe general case of sampling rate conversion<br />

by afactor I/D, the filtering can be accomplished by means of the linear<br />

time-variant filter described by the response function<br />

g(n, m) =h[nI − ((mD)) I ] (9.68)<br />

where h(n) is the impulse response of the low-pass FIR filter, which<br />

ideally, has the frequency response specified by (9.36). For convenience<br />

Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).<br />

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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