02.10.2019 Views

UploadFile_6417

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

294 Chapter 6 IMPLEMENTATION OF DISCRETE-TIME FILTERS<br />

4.0635 4.0635<br />

−0.0793<br />

−2.8255<br />

−1.6<br />

z −1<br />

−0.0815<br />

0.4<br />

z −1<br />

0.7747<br />

−0.63<br />

z −1<br />

−0.03<br />

z −1<br />

x(n)<br />

−0.8<br />

−0.5502<br />

z −1<br />

−0.2245<br />

1.2<br />

−0.2076<br />

z −1<br />

0.1319<br />

y(n)<br />

−0.15<br />

z −1<br />

−0.35<br />

z −1<br />

−2.4609<br />

−0.0304<br />

−0.1<br />

z −1<br />

−0.9<br />

z −1<br />

FIGURE P6.8 Structure for Problem 6.15<br />

1. Due to an error in labeling, two of the multiplier coefficients (rounded to 4 decimals) in<br />

this structure have incorrect values. Locate these 2 multipliers and determine their<br />

correct values.<br />

2. Determine and draw an overall cascade structure containing 2nd-order section and which<br />

contains the least number of multipliers.<br />

P6.16 As described in this chapter, a linear-phase FIR filter is obtained by requiring certain<br />

symmetry conditions on its impulse responses.<br />

1. In the case of symmetrical impulse response, we have h(n) =h(M − 1 − n),<br />

0 ≤ n ≤ M − 1. Show that the resulting phase response is linear in ω and is given by<br />

̸ H ( e jω) ( ) M − 1<br />

= − ω, −π

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!