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Quantization of Filter Coefficients 285<br />

Log-Mag Plot: 16-bits (1+2+13)<br />

Log-Mag Plot: 8-bits (1+2+13)<br />

0<br />

0<br />

−20<br />

−20<br />

Decibels<br />

−40<br />

Decibels<br />

−40<br />

−60<br />

True<br />

16-bit<br />

−60<br />

True<br />

8-bit<br />

−80<br />

0 0.2 0.4 0.6 0.8 1<br />

Digital Frequency in π Units<br />

PZ Plot: 16-bits (1+2+13)<br />

1<br />

−80<br />

0 0.2 0.4 0.6 0.8 1<br />

Digital Frequency in π Units<br />

PZ Plot: 8-bits (1+2+5)<br />

1<br />

Imaginary Part<br />

0.5<br />

0<br />

−0.5<br />

16-bit zero<br />

16-bit pole<br />

True zero<br />

True pole<br />

Imaginary Part<br />

0.5<br />

0<br />

−0.5<br />

8-bit zero<br />

8-bit pole<br />

True zero<br />

True pole<br />

−1<br />

−1<br />

−1 −0.5 0 0.5 1<br />

−1<br />

Real Part<br />

FIGURE 6.34 Plots for the IIR filter in Example 6.28<br />

−0.5 0 0.5<br />

Real Part<br />

1<br />

6.8.4 FIR FILTERS<br />

A similar analysis can be done for FIR filters. Let the impulse response<br />

of an FIR filter be h(n) with system response<br />

Then,<br />

H(z) =<br />

∆H(z) =<br />

M−1<br />

∑<br />

n=0<br />

M−1<br />

∑<br />

n=0<br />

h(n)z −n (6.78)<br />

∆h(n)z −n (6.79)<br />

where ∆H(z) isthe change due to change in the impulse response h(n).<br />

Hence<br />

∆H (e jω )=<br />

M−1<br />

∑<br />

n=0<br />

∆h(n)e −jωn or |∆H(e jω )|≤<br />

M−1<br />

∑<br />

n=0<br />

|∆h(n)| (6.80)<br />

Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).<br />

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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