Basic Analysis – Gently Done Topological Vector Spaces
Basic Analysis – Gently Done Topological Vector Spaces
Basic Analysis – Gently Done Topological Vector Spaces
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102 <strong>Basic</strong> <strong>Analysis</strong><br />
The next result we shall need is Hölder’s inequality.<br />
Theorem 9.7 Let p > 1 and let q be such that 1 1<br />
+ = 1 (q is called the<br />
p q<br />
exponent conjugate to p.) Then, for any x = (x n ) ∈ ℓ p and y = (y n ) ∈ ℓ q ,<br />
∞�<br />
n=1<br />
|x n y n | ≤ �x� p �y� q .<br />
If p = 1, the above inequality is valid if we set q = ∞.<br />
Proof The case p = 1 and q = ∞ is straightforward, so suppose that p > 1.<br />
Without loss of generality, we may suppose that �x�p = �y�q = 1. We then let<br />
α = 1 1<br />
, β =<br />
p q , a = |xn |p , b = |yn | q and use the previous proposition.<br />
Proposition 9.8 For any x = (x n ) ∈ ℓ p , with p > 1,<br />
�x� p = sup{ � � ∞ �<br />
n=1<br />
x n y n<br />
�<br />
� : �y�q = 1}.<br />
The equality also holds for the pairs p = 1 and q = ∞, and p = ∞, q = 1.<br />
Proof Hölder’s inequality implies that the right hand side is not greater than the<br />
lefthandside. Fortheconverse, consider y = (y n )withy n = sgnx n |x n | p/q /�x� p/q<br />
if 1 < p < ∞, with y n = sgnx n if p = 1, and with y n = (δ nm ) m∈N , if p = ∞.<br />
As an immediate corollary, we obtain Minkowski’s inequality.<br />
Corollary 9.9 For any p ≥ 1 and x,y ∈ ℓ p , we have x+y ∈ ℓ p and<br />
�x+y� p ≤ �x� p +�y� p .<br />
Proof This follows from the triangle inequality and the preceding proposition.<br />
Department of Mathematics King’s College, London