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Basic Analysis – Gently Done Topological Vector Spaces

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7: Locally Convex <strong>Topological</strong> <strong>Vector</strong> <strong>Spaces</strong> 71<br />

Next, we observe that (i) implies that there is some neighbourhood U of 0 such<br />

that ρ(U) ⊆ {t ∈ K : |t| < 1}, i.e., |ρ(x)| < 1 whenever x ∈ U and so (iii) holds.<br />

Conversely, if (iii) holds, there is some neighbourhood V of 0 and some constant<br />

C > 0 such that |ρ(x)| < C for any x ∈ V. It follows that for any ε > 0, |ρ(x)| < ε<br />

V and so ρ is continuous at 0, which is (i).<br />

whenever x ∈ C<br />

ε<br />

Finally, we show that (i) implies (iv). So suppose that ρ is continuous at 0.<br />

Then there is a neighbourhood U of 0 such that ρ(U) ⊆ {t ∈ R : |t| < 1}, that<br />

is, ρ(x) < 1 whenever x ∈ U. But there are p1 ,...,p m in P and r > 0 such that<br />

V(0,p 1 ,...,p m ;r) ⊆ U, and therefore ρ(x) < 1 for all x ∈ V(0,p 1 ,...,p m ;r).<br />

Let s(x) = p1 (x) + ··· + pm (x) and suppose x is such that s(x) �= 0. Then<br />

rx/s(x) ∈ V(0,p 1 ,...,p m ;r) and so ρ(rx/s(x)) < 1, that is,<br />

ρ(x) < 1 �<br />

p1 (x)+···+p m (x)<br />

r<br />

� .<br />

On the other hand, if s(x) = 0, then s(nx) = 0 for any n ∈ N. Hence nx ∈<br />

V(0,p 1 ,...,p m ;r) and so ρ(nx) = nρ(x) < 1 for all n ∈ N. This forces ρ(x) = 0<br />

and we conclude that, in any event,<br />

for all x ∈ X.<br />

ρ(x) ≤ 1 �<br />

p1 (x)+···+p m (x)<br />

r<br />

�<br />

Corollary 7.9 Suppose that Λ : X → K is a linear functional on a topological<br />

vector space (X,T), where T is the vector space topology determined by a family<br />

P of seminorms on X. The following statements are equivalent.<br />

(i) Λ is continuous at 0.<br />

(ii) Λ is continuous.<br />

(iii) There is a finite set of seminorms p 1 ,...,p m in P and a constant C > 0<br />

such that<br />

|Λ(x)| ≤ C(p 1 (x)+···+p m (x)) for x ∈ X.<br />

If F is a family of linear functionals on X such that P is the collection P = {|ℓ| :<br />

ℓ ∈ F}, then (i), (ii) and (iii) are equivalent to the following.<br />

(iv) There is a finite set ℓ 1 ,...,ℓ m of members of F and s 1 ,...,s m ∈ K such<br />

that<br />

Λ(x) = s 1 ℓ 1 (x)+···+s m ℓ m (x) for x ∈ X.<br />

Proof We know already that (i) and (ii) are equivalent, by Proposition 6.19. For<br />

x ∈ X, set ρ(x) = |Λ(x)|. Then ρ is a seminorm on X. To say that ρ is continuous

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