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Basic Analysis – Gently Done Topological Vector Spaces

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90 <strong>Basic</strong> <strong>Analysis</strong><br />

Proposition 8.7 For any closed linear subspace M of a Banach space X, the<br />

quotient space X/M is a Banach space under the quotient norm.<br />

Proof We know that X/M is a normed space, so all that remains is to show<br />

that it is complete. We use the criterion established above. Suppose, then, that<br />

([xn ]) is any sequence in X/M such that �<br />

n�[xn ]� < ∞. We show that there is<br />

[y] ∈ X/M such that �k n=1 [xn ] → [y] as k → ∞.<br />

For each n, �[xn ]� = infm∈M �xn + m�, and therefore there is mn ∈ M such<br />

that<br />

�xn +mn� ≤ �[xn ]�+ 1<br />

,<br />

2n by definition of the infimum. Hence<br />

�<br />

�xn +mn� ≤ ��<br />

�[xn ]�+ 1<br />

2n �<br />

n<br />

n<br />

< ∞.<br />

But(x n +m n )isasequenceintheBanachspaceX, andsolim k→∞<br />

exists in X. Denote this limit by y. Then we have<br />

�<br />

�<br />

k�<br />

[xn ]−[y] � �<br />

k�<br />

� = � [xn −y] � �<br />

n=1<br />

n=1<br />

�<br />

k�<br />

= inf � xn −y +m � �<br />

≤ � �<br />

= � �<br />

m∈M<br />

n=1<br />

k�<br />

xn −y +<br />

n=1<br />

k�<br />

n=1<br />

�<br />

m �<br />

n<br />

k�<br />

(xn +mn )−y � �<br />

n=1<br />

→ 0, as k → ∞.<br />

� k<br />

n=1 (x n +m n )<br />

Hence �k n=1 [xn ] → [y] as k → ∞ and we conclude that X/M is complete.<br />

Example 8.8 Let X be the linear space C([0,1]) and let M be the subset of X<br />

consisting of those functions which vanish at the point 0 in [0,1]. Then M is a<br />

linear subspace of X and so X/M is a vector space.<br />

Define themapφ : X/M → Cbysettingφ([f]) = f(0), for[f] ∈ X/M. Clearly,<br />

φ is well-defined (if f ∼ g then f(0) = g(0)) and we have<br />

φ(t[f]+s[g]) = φ([tf +sg])<br />

= tf(0)+sg(0)<br />

= tφ([f])+sφ([g])<br />

Department of Mathematics King’s College, London

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