24.12.2012 Views

Basic Analysis – Gently Done Topological Vector Spaces

Basic Analysis – Gently Done Topological Vector Spaces

Basic Analysis – Gently Done Topological Vector Spaces

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

2. Nets<br />

In a metric space, a point belongs to the closure of a given set if and only if it is<br />

the limit of some sequence of points belonging to that set. The convergence of the<br />

sequence (a n ) n∈N to the point x is defined by the requirement that for any ε > 0<br />

there is N ∈ N such that the distance between a n and x is less than ε whenever<br />

n ≥ N. This is equivalent to the requirement that for any neighbourhood U of<br />

x there is some N ∈ N such that a n belongs to U whenever n ≥ N. We take<br />

this latter formulation, word for word, as the definition of convergence of the<br />

sequence (a n ) n∈N in an arbitrary topological space. The resulting theory is not as<br />

straightforward as one might suspect, as is illustrated by the following example.<br />

Example 2.1 LetX betherealinterval[0,1]andletTbetheco-countabletopology<br />

on X; that is, T consists of X and ∅ together with all those subsets G of X whose<br />

complement X\G isacountable set. Let A = [0,1), and consider A. Now, {1} /∈ T<br />

because X \{1} = [0,1) is not countable. It follows that the complement of {1}<br />

is not closed. That is to say, A is not closed. However, the closure of A is closed<br />

and contains A. This means that we must have A = [0,1], since [0,1] is the only<br />

closed set containing A. Since 1 is not an element of A, it must be a limit point<br />

of A.<br />

Is there some sequence in A which converges to 1? Suppose that (a n ) n∈N is<br />

any sequence in A whatsoever. Let B = {a 1 ,a 2 ,...} and let G = X \ B. Then<br />

1 ∈ G. Since B is countable, it follows from the definition of the topology on X<br />

that G is open. Thus G is an open neighbourhood of 1 which contains no member<br />

of the sequence (a n ) n∈N . Clearly, (a n ) n∈N cannot converge to 1. No sequence in<br />

A can converge to the limit point 1. We have exhibited a topological space with<br />

a subset possessing a limit point which is not the limit of any sequence from the<br />

subset.<br />

This example indicates that sequences may not be as useful in topological<br />

spaces as they are in metric spaces. One can, at this point, choose to abandon the<br />

use of sequences, except perhaps in favourable situations, or to seek some form<br />

of replacement. It turns out that one can keep the intuition of sequences but at<br />

the cost of an increase in formalism. As perhaps suggested by the previous ex-<br />

13

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!