Basic Analysis – Gently Done Topological Vector Spaces
Basic Analysis – Gently Done Topological Vector Spaces
Basic Analysis – Gently Done Topological Vector Spaces
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122 <strong>Basic</strong> <strong>Analysis</strong><br />
Corollary 10.23 Suppose that X and Y are Banach spaces and that T : X → Y is<br />
a one-one continuous linear mapfrom X onto Y. Then there arepositiveconstants<br />
a and b such that<br />
a�x� ≤ �T(x)� ≤ b�x�<br />
for all x ∈ X.<br />
Proof By the corollary, S = T −1 is continuous, and so there is some C > 0 such<br />
�S(y)� ≤ C�y� for all y ∈ Y. Replacing y by T(x) and setting a = C −1 , it follows<br />
that<br />
a�x� = a�S(y)� ≤ �y� = �T(x)�, for x ∈ X.<br />
The continuity of T implies that �T(x)� ≤ b�x� for some positive constant b and<br />
all x ∈ X.<br />
Corollary 10.24 Suppose that T 1 ⊆ T 2 are vector topologies on a vector space<br />
X, such that X is a Fréchet space with respect to both. Then T 1 = T 2 .<br />
Proof The identity map from (X,T 2 ) → (X,T 1 ) is a one-one continuous linear<br />
map. By the open mapping theorem, it is open, and therefore every T 2 open set<br />
is also T 1 open, i.e., T 2 ⊆ T 1 , and so equality holds.<br />
If X and Y are vector spaces over K (either both over R or both over C) then<br />
the Cartesian product X × Y is a vector space when equipped with the obvious<br />
component-wise linear operations, namely t(x,y) = (tx,ty) and (x,y)+(x ′ ,y ′ ) =<br />
(x+x ′ ,y+y ′ ) for any t ∈ K, x,x ′ ∈ X and y,y ′ ∈ Y. If X and Y are topological<br />
vector spaces, then X ×Y can be equipped with the product topology. It is not<br />
difficult to see that this is a vector topology thus making X×Y into a topological<br />
) are nets in X × Y converging to<br />
vector space. Indeed, if (xν ,yν ) and (x ′ ν ,y′ ν<br />
(x,y) and (x ′ ,y ′ ), respectively, then xν → x and x ′ ν → x′ in X and yν → y and<br />
y ′ ν → y′ in Y. It follows that xν +x ′ ν → x+x′ and yν +y ′ ν → y+y′ and therefore<br />
(xν ,yν ) + (x ′ ν ,y′ ν ) → (x + x′ ,y + y ′ ) in X × Y. Thus addition is continuous in<br />
X ×Y. In a similar way, one sees that scalar multiplication is continuous.<br />
Now, if X and Y are Fréchet spaces, then so is X × Y. In fact, if {pn } and<br />
{qn } are countable families of determining seminorms for X and Y, respectively,<br />
then {ρn } is a determining family for the product topology on X ×Y, where ρn is given by<br />
ρn ((x,y)) = pn (x)+q n (y)<br />
for n ∈ N and (x,y) ∈ X ×Y. The fact that this family does indeed determine<br />
the product topology on X × Y follows from the equivalence of the following<br />
statements; (x ν ,y ν ) → (x,y)inX×Y, x ν → xinX andy ν → y inY, p n (x ν −x) →<br />
Department of Mathematics King’s College, London