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Basic Analysis – Gently Done Topological Vector Spaces

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28 <strong>Basic</strong> <strong>Analysis</strong><br />

Proposition 3.7 Suppose that F is any collection of subsets of a given set X<br />

satisfyingthefip. ThenthereisamaximalcollectionDcontaining Fandsatisfying<br />

the fip, i.e., if F ⊆ F ′ and if F ′ satisfies the fip, then F ′ ⊆ D. Furthermore,<br />

(i) if A 1 ,...,A n ∈ D, then A 1 ∩···∩A n ∈ D, and<br />

(ii) if A is any subset of X such that A∩D �= ∅ for all D ∈ D, then A ∈ D.<br />

Proof As might be expected, we shall use Zorn’s lemma. Let C denote the<br />

collection of those families of subsets of X which contain F and satisfy the fip.<br />

Then F ∈ C, so C is not empty. Evidently, C is ordered by set-theoretic inclusion.<br />

Suppose that Φ is a totally ordered set of families in C. Let A = �<br />

S. Then<br />

F ⊆ A, since F ⊆ S, for all S ∈ Φ. We shall show that A satisfies the fip. To<br />

see this, let S1 ,...,S n ∈ A. Then each Si is an element of some family Si that<br />

belongs to Φ. But Φ is totally ordered and so there is i0 such that Si ⊆ S for all i0<br />

1 ≤ i ≤ n. Hence S1 ,...,S n ∈ Si0 and so S1 ∩···∩S n �= ∅ since S satisfies the i0<br />

fip. It follows that A is an upper bound for Φ in C. Hence, by Zorn’s lemma, C<br />

contains a maximal element, D, say.<br />

(i) Now suppose that A 1 ,...,A n ∈ D and let B = A 1 ∩···∩A n . Let D ′ = D∪{B}.<br />

Then any finite intersection of members of D ′ is equal to a finite intersection of<br />

members of D. Thus D ′ satisfies the fip. Clearly, F ⊆ D ′ , and so, by maximality,<br />

we deduce that D ′ = D. Thus B ∈ D.<br />

(ii) Suppose that A ⊆ X and that A∩D �= ∅ for every D ∈ D. Let D ′ = D∪{A},<br />

and let D 1 ,...,D m ∈ D ′ . If D i ∈ D, for all 1 ≤ i ≤ m, then D 1 ∩···∩D m �= ∅<br />

since D satisfies the fip. If some D i = A and some D j �= A, then D 1 ∩···∩D m<br />

has the form D 1 ∩···∩D k ∩A with D 1 ,...,D k ∈ D. By (i), D 1 ∩···∩D k ∈ D<br />

and so, by hypothesis, A∩(D 1 ∩...D k ) �= ∅. Hence D ′ satisfies the fip and, again<br />

by maximality, we have D ′ = D and thus A ∈ D.<br />

We are now ready to prove Tychonov’s theorem which states that the product<br />

of compact topological spaces is compact with respect to the product topology. In<br />

fact we shall present three proofs. The first is based on the previous proposition,<br />

the second (due to P. Chernoff) uses the idea of partial cluster points together<br />

with Zorn’s lemma, and the third uses universal nets.<br />

Department of Mathematics King’s College, London<br />

S∈Φ

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