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Módulo de Cálculo

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4.1 Propieda<strong>de</strong>s <strong>de</strong> la continuidad <strong>Cálculo</strong> Diferencial<br />

el teorema <strong>de</strong>l valor intermedio sea continua. En general, el teorema <strong>de</strong>l valor intermedio no se<br />

cumple para funciones discontinuas.<br />

EJERCICIOS .2 : Realice la gráca <strong>de</strong><br />

cada función y halle los puntos <strong>de</strong> discontinuidad<br />

(si los hay).<br />

1. f (x) = x3<br />

2<br />

2. f (x) = x2 1<br />

x<br />

3. f (x) = x2 1<br />

x + 1<br />

4. f (x) = 1<br />

x 2 4<br />

<br />

x si x < 1<br />

5. f (x) =<br />

2x 1 si x > 1<br />

6. f (x) = bxc<br />

2 + x<br />

Hallar las discontinuida<strong>de</strong>s (si las<br />

hay) <strong>de</strong> la función dada.¿cúales son<br />

evitables<br />

7. f (x) = x 2 2x + 1<br />

8. f (x) = 1<br />

x 1<br />

9. f (x) = x<br />

x 2 + 1<br />

10. f (x) =<br />

x + 2<br />

x 2 3x 10<br />

11. f (x) = 1<br />

x 2 + 1<br />

12. f (x) = x<br />

x 2 1<br />

13. f (x) = x 3<br />

x 2 9<br />

14. f (x) = x 1<br />

x 2 + x 2<br />

x x 1<br />

15. f (x) =<br />

x 2 x > 1<br />

2x + 3 x < 1<br />

16. f (x) =<br />

x 2 x 1<br />

x<br />

17. f (x) =<br />

+ 1 x 2<br />

2<br />

3 x x > 2<br />

<br />

2x x 2<br />

18. f (x) =<br />

x 2 4x + 1 x > 2<br />

19. f (x) =<br />

[x + 2]<br />

x + 2<br />

[x 3]<br />

20. f (x) =<br />

x 3<br />

[x 2] + 3 x < 0<br />

21. f (x) =<br />

x + 5 x 0<br />

<br />

3 + x x 2<br />

22. f (x) =<br />

x 2 + 1 x > 2<br />

23. f (x) = kx 1k<br />

24. f (x) = x kxk<br />

Arenas A. 38 Camargo B.

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