Descargar (1482Kb) - Universidad de El Salvador
Descargar (1482Kb) - Universidad de El Salvador
Descargar (1482Kb) - Universidad de El Salvador
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0.4 cm ______ 1.2 kg = 2.2 cm* 1.2 Kg = 6.6 Kgf2.2 cm ______ X 0.4 cmF max. = 6.6 KgfS= 2.2 cm K= 6.6 Kgf = 3.0 Kgf/cm o 30 N/cm2.2 cmK= 3.0 Kgf/cm * 2.2 lbf/kgf * 2.54 cm/plug = 16.76 Lbf/pulg= 30 N/cm * 100cm/1m = 3000 N/m = 300 Kgf/cm70