Sophie Germain: mathématicienne extraordinaire - Scripps College
Sophie Germain: mathématicienne extraordinaire - Scripps College
Sophie Germain: mathématicienne extraordinaire - Scripps College
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<strong>Sophie</strong> <strong>Germain</strong>’s Theorems 59<br />
fied and if there are integer solutions x, y, and z to the equation X p + Y p + Z p = 0,<br />
then exactly one of x, y, or z is a multiple of p. This concludes our proof of<br />
<strong>Sophie</strong> <strong>Germain</strong>’s Theorem. □<br />
<strong>Sophie</strong> <strong>Germain</strong> found auxiliary primes q for all primes up 100, thus<br />
proving Case 1 of Fermat’s Last Theorem for these 24 primes. She also<br />
found that for primes p > 2 such that q = 2p + 1 is also prime, conditions<br />
1 and 2 hold, as we will see below. These primes have come to be known<br />
as <strong>Sophie</strong> <strong>Germain</strong> primes. Her theorem applies to all <strong>Sophie</strong> <strong>Germain</strong><br />
primes, thus proving Case 1 of Fermat’s Last Theorem for all odd primes p<br />
such that q = 2p + 1 is also prime.<br />
<strong>Sophie</strong> <strong>Germain</strong> Primes Theorem 2. Let p be an odd prime with the property<br />
that q = 2p + 1 is also prime. Then conditions 1 and 2 hold. I.e.:<br />
1. n p ≢ p (mod q) for all integers n.<br />
2. x p +y p +z p ≡ 0 (mod q) implies that q|xyz where x, y, and z are relatively<br />
prime.<br />
Proof of the <strong>Sophie</strong> <strong>Germain</strong> Primes Theorem. Consider an integer n.<br />
Clearly if n ≡ 0 (mod q), then, since q ∤ p,<br />
n p ≡ 0 (mod q)<br />
≢<br />
p (mod q).<br />
Fermat’s Little Theorem tells us that when q is an odd prime, n q−1 ≡ 1 (mod q)<br />
for any integer n ≢ 0 (mod q).