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Sophie Germain: mathématicienne extraordinaire - Scripps College

Sophie Germain: mathématicienne extraordinaire - Scripps College

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<strong>Sophie</strong> <strong>Germain</strong>’s Theorems 59<br />

fied and if there are integer solutions x, y, and z to the equation X p + Y p + Z p = 0,<br />

then exactly one of x, y, or z is a multiple of p. This concludes our proof of<br />

<strong>Sophie</strong> <strong>Germain</strong>’s Theorem. □<br />

<strong>Sophie</strong> <strong>Germain</strong> found auxiliary primes q for all primes up 100, thus<br />

proving Case 1 of Fermat’s Last Theorem for these 24 primes. She also<br />

found that for primes p > 2 such that q = 2p + 1 is also prime, conditions<br />

1 and 2 hold, as we will see below. These primes have come to be known<br />

as <strong>Sophie</strong> <strong>Germain</strong> primes. Her theorem applies to all <strong>Sophie</strong> <strong>Germain</strong><br />

primes, thus proving Case 1 of Fermat’s Last Theorem for all odd primes p<br />

such that q = 2p + 1 is also prime.<br />

<strong>Sophie</strong> <strong>Germain</strong> Primes Theorem 2. Let p be an odd prime with the property<br />

that q = 2p + 1 is also prime. Then conditions 1 and 2 hold. I.e.:<br />

1. n p ≢ p (mod q) for all integers n.<br />

2. x p +y p +z p ≡ 0 (mod q) implies that q|xyz where x, y, and z are relatively<br />

prime.<br />

Proof of the <strong>Sophie</strong> <strong>Germain</strong> Primes Theorem. Consider an integer n.<br />

Clearly if n ≡ 0 (mod q), then, since q ∤ p,<br />

n p ≡ 0 (mod q)<br />

≢<br />

p (mod q).<br />

Fermat’s Little Theorem tells us that when q is an odd prime, n q−1 ≡ 1 (mod q)<br />

for any integer n ≢ 0 (mod q).

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