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Sophie Germain: mathématicienne extraordinaire - Scripps College

Sophie Germain: mathématicienne extraordinaire - Scripps College

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What then 64<br />

p, 6p + 1” [9] explains why these pairs are exceptional and how to prove<br />

Case 1 of Fermat’s Last Theorem for such primes.<br />

What possibilities are left<br />

In general, <strong>Sophie</strong> <strong>Germain</strong>’s Theorem precludes<br />

most solutions x, y, and z to the equation X n +Y n = Z n where none<br />

of the integers x, y, or z is divisible by n. We have already discussed the<br />

impossibility of equations where n is divisible by 4. We have also seen that<br />

when n is divisible by 2, any the squares of any solutions to the equation<br />

X n +Y n = Z n are solutions to X n 2 +Y n 2<br />

= Z n 2 . So we consider the non-zero<br />

integer solutions to the equation<br />

X P + Y P + Z P = 0<br />

where P is a product of primes greater than 2.<br />

We know that one of X, Y , or Z is divisible by P , without loss of generality<br />

we assume X = aP for some integer a. Then (aP ) P + Y P + Z P = 0.<br />

There are a few good number theoretic tools which help narrow down<br />

possible solutions. We will consider only Fermat’s Little Theorem and the<br />

Chinese Remainder Theorem, but there are other interesting approaches,<br />

many of which are discussed at length in [23].<br />

We recall Fermat’s Little Theorem,<br />

a p ≡ a (mod )<br />

for any integer a where p is prime.

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