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Het Stomachion - KNAW Onderwijsprijs

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H (afbeelding 19):<br />

-­‐ Hoek DEA = hoek BAE = 90°, dat is gegeven.<br />

-­‐ Hoek HBJ = 45°, dus Hoek ABC = 135°.<br />

-­‐ Omdat hoek CDF = λ, is hoek CDE = 180° – λ<br />

-­‐ Hoek DCG = λ, dus hoek BCE = 45° + λ.<br />

Afbeelding 19: puzzelstuk H<br />

26

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